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Tanzania [10]
4 years ago
6

Expand(2a+3b)^5using binomial theorem

Mathematics
1 answer:
TiliK225 [7]4 years ago
3 0

Answer:

32a⁵ + 240a⁴b + 720a³b² + 1080a²b³ + 810ab⁴ + 243b⁵

Step-by-step explanation:

(2a+3b)⁵ = (2a)⁵ + 5C1(2a)⁴(3b)¹

+ 5C2(2a)³(3b)² +

+ 5C3(2a)²(3b)³ +

+ 5C4(2a)¹(3b)⁴ +

+ (3b)⁵

= 32a⁵ + 240a⁴b + 720a³b² +

1080a²b³ + 810ab⁴ + 243b⁵

(Correct me if i am wrong)

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What is 30% as a fraction
krok68 [10]
 = 30%

= 0.3

= 3/10

Hope this helps.
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3 years ago
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What is the slope of the line that passes through (8,4) and (6,7)?
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slope=\frac{y_2-y_1}{x_2-x_1}\\\\ 
(x_1,y_1)=(8,4)\\ 
(x_2,y_2)=(6,7)\\\\
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Slope\ is\ equal\ to\ -\frac{3}{2}.

4 0
3 years ago
Mathematics algebra​
Alexxx [7]

Answer:

⇒  1\frac{1}{3}m-1\frac{1}{2}n-4\frac{1}{2}

Step-by-step explanation:

  • \frac{4m}{3}-\frac{3(n+3)}{2}
  • \frac{4m}{3}-\frac{3n+9}{2}
  • \frac{4m}{3}-\frac{3n}{2}-\frac{9}{2}
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5 0
4 years ago
The arch beneath a bridge is​ semi-elliptical, a​ one-way roadway passes under the arch. The width of the roadway is 38 feet and
forsale [732]

Answer:

Only truck 1 can pass under the bridge.

Step-by-step explanation:

So, first of all, we must do a drawing of what the situation looks like (see attached picture).

Next, we can take the general equation of an ellipse that is centered at the origin, which is the following:

\frac{x^2}{a^2}+\frac{y^2}{b^2}

where:

a= wider side of the ellipse

b= shorter side of the ellipse

in this case:

a=\frac{38}{2}=19ft

and

b=12ft

so we can go ahead and plug this data into the ellipse formula:

\frac{x^2}{(19)^2}+\frac{y^2}{(12)^2}

and we can simplify the equation, so we get:

\frac{x^2}{361}+\frac{y^2}{144}

So, we need to know if either truk will pass under the bridge, so we will match the center of the bridge with the center of each truck and see if the height of the bridge is enough for either to pass.

in order to do this let's solve the equation for y:

\frac{y^{2}}{144}=1-\frac{x^{2}}{361}

y^{2}=144(1-\frac{x^{2}}{361})

we can add everything inside parenthesis so we get:

y^{2}=144(\frac{361-x^{2}}{361})

and take the square root on both sides, so we get:

y=\sqrt{144(\frac{361-x^{2}}{361})}

and we can simplify this so we get:

y=\frac{12}{19}\sqrt{361-x^{2}}

and now we can evaluate this equation for x=4 (half the width of the trucks) so:

y=\frac{12}{19}\sqrt{361-(8)^{2}}

y=11.73ft

this means that for the trucks to pass under the bridge they must have a maximum height of 11.73ft, therefore only truck 1 is able to pass under the bridge since truck 2 is too high.

5 0
3 years ago
Please help me with this use the screen shot
dezoksy [38]
Okay so this is a wild guess but I would say 12. The whole angle is 90, but only 1/3 of that is in the smaller portion of the triangle. So, I assumed that 1/3 of the length of the whole triangle. Three times 6 is 18 and minus AD is 12. So BD=12? This is my best guess hope it helps
4 0
3 years ago
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