Answer:
The ship S is at 10.05 km to coastguard P, and 12.70 km to coastguard Q.
Step-by-step explanation:
Let the distance of the ship to coastguard P be represented by x, and its distance to coastguard Q be represented by y.
But,
<P = 048°
<Q =
- 
= 0
Sum of angles in a triangle = 
<P + <Q + <S = 
048° + 0
+ <S = 
+ <S = 
<S =
- 
= 
<S = 
Applying the Sine rule,
=
= 
= 
= 
= 
⇒ y = 
= 12.703
y = 12.70 km
= 
= 
= 
⇒ x = 
= 10.0475
x = 10.05 km
Thus,
the ship S is at a distance of 10.05 km to coastguard P, and 12.70 km to coastguard Q.
-⅔ (6x + 9) = 18
Apply distributive property. Multipy -⅔ to 6x and 9.
-4x - 6 = 18
Add 6 to both sides so -4x can be alone.
-4x - 6 + 6 = 18 + 6
-4x = 24
To get x alone, divide both sides by -4.
-4/-4x = 24/-4
x = -6
x = -6 is your answer. I hope this helps! Let me know if you need more help or if I got something wrong.
It would be D. 5/20 because the other 2 you would add then subtract and then you would just put the answer yo get from subtracting it over 20.
You have to find the angle for it try it!!!!!!!!!!
Here is the answer with my work !!