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lisabon 2012 [21]
3 years ago
12

John cut a paper square with a perimeter of 18 inches into two rectangles. The perimeter of one of the rectangles is 10 inches.

What is the perimeter of the second rectangle?
Mathematics
2 answers:
koban [17]3 years ago
3 0

Answer:

17 inches

Step-by-step explanation:

The original square had sides of 4.5 (18/4)

To get a perimeter of 10, we know that two sides would already equal 9 (4.5+4.5).  That means we only have 1 inch for the other two sides, so they are each 1/2 inch.

That leaves the second rectangle with a length and width of 4.5 and 4.

2(4.5) + 2(4) =

9+8=

17

otez555 [7]3 years ago
3 0

Answer:

17 in

Step-by-step explanation:

2(4.5) + 2(4)

=9+8

=17

Hope this helps!

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The answer is 1,200 but all you have to do is figure out what 4% of 5000 is and then multiply that by 6

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Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. x = e−5t
Elan Coil [88]

Answer:

x = 1 - 5t

y = t

z = 1 - 5t

Step-by-step explanation:

For the equation of a line, we need a point and a direction vector. We are given a point (1, 0, 1).

Since the line is suppose to be a tangent to the given curve at the point (1, 0, 1), we need to find a tangent vector for which the curve passes through that point.

We have x = e^(-5t)cos5t

at t = 1, x = e^(-5)cos5

at t = 0, x = 1

y = e^(-5t)sin5t

at t = 1, y = e^(-5)sin5

at t = 0, y = 0

z = e^(-5t)

at t = 1, z = e^(-5)

at t = 0, z = 1

Clearly, the only parameter value for which the curve passes through the point (1, 0, 1) is t = 0.

In vector notation, the curve

r(t) = xi + yj + zk

= e^(-5t)cos5t i + e^(-5t)sin5t j + e^(-5t) k

r'(t) = [-5e^(-5t)cos5t - e^(-5t)sin5t] i +[e^(-5t)cos5t - 5e^(-5t)sin5t] j - 5e^(-5t) k

r'(0) = -5i + j - 5k

is a vector tangent at the point.

We get the parametric equation from this.

x = x(0) + tx'(0)

= 1 - 5t

y = y(0) + ty'(0)

= t

z = z(0) + tz'(0)

= 1 - 5t

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Simplify the expression
Molodets [167]

Answer:

8x^8/3 y^4 - The first option

Step-by-step explanation:

The first thing we need to do is the exponent outside the bracket and leave the 8 till last, because exponents always come before multiplying coefficients. When an term with an exponent is multiplied by another exponent outside a bracket, the exponents of both terms are multiplied by the exponent outside the bracket.

This means that the expression is now:

8(x^2*4/3 y^3*4/3)

First we can so the x term. The x term already has an exponent of 2, so the 2 is multiplied by the 4/3 exponent outside the bracket. 2*4/3 = 8/3, so the x term is now: x^8/3

The same happens to the y term: 3*4/3 simplifies to 4, so the y term is now y^4.

So now our expression is:

8(x^8/3 y^4)

Now the 8 outside the bracket simply multiplies on to the whole term so we finish with:

8x^8/3 y^4 - The first option.

Hope this helped!

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