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dexar [7]
3 years ago
14

I need to know what the value is for x

Mathematics
1 answer:
hoa [83]3 years ago
6 0
4/6 = x + 3/ 12 - x
4( 12 - x) = 6( x + 3)
48 - 4x = 6x + 18
-4x - 6x = 18 - 48
- 10x = -30
x = 3
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Which term can be added to the list so that greatest common factor of the three terms is 12h^3? 36h^3 12h^6. 6h^3. 12h^2. 30h^4.
Juliette [100K]

Answer:

Last Option 48h^{5}.

Step-by-step explanation:

In this question we will do the factors of given two terms then we will do the common factors of all the terms given in answer to match with.

Common factors of 36h³ = 1×2×2×3×3×h×h×h

Common factors of 12h^{6} = 1×2×2×3×h×h×h×h×h×h

In these two terms greatest common factor Of these two terms is = 1×2×2×3×h×h×h = 12h³

Therefore the third term will be the number which has the greatest common factor = 12h³

So the given terms are

6h³ = 1×2×3×h×h×h

12h² = 1×2×2×3×h×h

30h^{4} = 1×2×3×5×h×h×h×h

48h^{5} = 1×2×2×2×2×3×h×h×h×h×h

Therefore the greatest common factor of the term which matches with 12h³ is 48h^{5}

3 0
2 years ago
HELP PLEASE CAN’T FIGURE THIS OUT NEED HELP
Ivanshal [37]

Answer:

LN= 68°

Step-by-step explanation:

6 0
3 years ago
a baby blue whale weighed 5200 lbs birth. after 2 days the baby weighed 5710. after 14 days the baby weighed 8180 lbs is it prop
sveticcg [70]

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Step-by-step explanation:

6 0
3 years ago
2 Which of the following polynomials is not written in standard form?
Varvara68 [4.7K]

Answer:

3

Step-by-step explanation:

Standard form is written in the order of the exponent <em>on</em><em> </em><em>a</em><em> </em><em>variable</em> from highest to lowest.

#1 exponents go 2, 1 , then zero. So, this is standard form.

#2 exponents go 2 then zero, so this is standard form.

#3 exponents go 1 then 2 then zero, so this is <em><u>not</u></em> in standard form.

#4 exponents go 3 to 2 to 1, so this is still in standard form.

hope this helps!

8 0
3 years ago
How many times can 6 go into 58
swat32
58 ÷ 6 = 9/2/3

i am a mathematics teacher. if anything to ask please pm me
4 0
3 years ago
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