Answer: 3/5
Step-by-step explanation: 3/5 is equal to .6 so if is greater than .5625
Half one is 1/2;
half three is 3/2;
Thus, if f(x) represents annual growth, f(x)/2 shows it every half-year, like this:
![\dfrac{f(x)}{2} = \dfrac{15\cdot 2^x}{2} \\ \\ \dfrac{f(x)}{2} = \dfrac{15}{2}\cdot 2^x](https://tex.z-dn.net/?f=%5Cdfrac%7Bf%28x%29%7D%7B2%7D%20%3D%20%5Cdfrac%7B15%5Ccdot%202%5Ex%7D%7B2%7D%20%5C%5C%20%20%5C%5C%20%0A%5Cdfrac%7Bf%28x%29%7D%7B2%7D%20%3D%20%5Cdfrac%7B15%7D%7B2%7D%5Ccdot%202%5Ex)
Written in plain text: f(x)=15/2*2^x
The answer is 35/10 and 6/10
Answer:
Part a) variable x (the number of adult tickets sold) and variable y (the number of child tickets sold)
Part b) ![10x+8y=1,276](https://tex.z-dn.net/?f=10x%2B8y%3D1%2C276)
Part c) The number of adult tickets sold was 86
Step-by-step explanation:
Part a) Name a variable for the number of adult tickets sold and name a variable for the number of child tickets sold
Let
x -----> the number of adult tickets sold
y -----> the number of child tickets sold
Part b) Write an equation in two variables to model the problem
we know that
-----> equation A
-----> equation B
substitute equation B in equation A and solve for x
![10x+8(52)=1,276](https://tex.z-dn.net/?f=10x%2B8%2852%29%3D1%2C276)
![10x+416=1,276](https://tex.z-dn.net/?f=10x%2B416%3D1%2C276)
Part c) Using your equation in Part B, solve the problem and answer the question "how many adult tickets did Anne sell?" i
we have
![10x+416=1,276](https://tex.z-dn.net/?f=10x%2B416%3D1%2C276)
Solve for x
Subtract 416 both sides
![10x=1,276-416](https://tex.z-dn.net/?f=10x%3D1%2C276-416)
![10x=860](https://tex.z-dn.net/?f=10x%3D860)
![x=86](https://tex.z-dn.net/?f=x%3D86)
therefore
The number of adult tickets sold was 86