B
Orbitals fill in a way that all of them first gain one electron, and then they start receiving the second electron if any are left. Thus, the three will fill with one electron each first and then the fourth will go into the first.
I think The answer to two is it would sink
Answer:
2C2H6(g) + 7O2(g) ==> 4CO2(g) + 6H2O(g)
One way to find the limiting reactant is to divide the moles of reactant by the corresponding coefficient in the balanced equation and whichever is less is limiting.
For C2H6 we have 2 moles / 2 = 1
For O2 we have 8 moles / 7 = 1.14
Explanation:
If a reaction mixture contains 8 moles of O2(g) with 2 moles of C2H6(g),which reactant is the limiting reactqnt and what is the mass (in grams) remaining of the reactant in excess?
They have a complete electronic configuration .their P shell is p6 therefore cannot gain or loose electron.
The tool to measure the liquid is a measuring cylinder.
