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denis23 [38]
2 years ago
12

as a bystander, the _______ approach doesn’t work when drugs or alcohol are involved, as the person you’re trying to stop is mor

e likely to become defensive or hostile.
Chemistry
1 answer:
tia_tia [17]2 years ago
7 0

When trying to step into an argument or misunderstanding between people as a <em>bystander with drugs and alcohol involved</em>, the direct approach won't work.

  • When trying to make peace between quarelling individuals as a bystander, the direct approach would <em>fail if alcohol or drugs is being held</em> as the prsin might see you as a villian.

  • Only when the person <em>knows and trusts you will this approach work</em>. Hence, when drugs or alcohol is involved, other methods of rendering help should be employed.

Therefore, the direct approach won't work in the this scenario.

Learn more :brainly.com/question/25170371

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When frequency increases, as does the energy, but wavelength decreases. It also works vise versa; if wavelength were to increase, its frequency and energy will decrease.
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2 years ago
Write the equilibrium expression of each chemical equation.<br> 2H2S(g) 2H2(g) + S2(g)
hodyreva [135]

Answer:

<u>[H2]2[S2][H2S]2Kc=[H2]2[S2][H2S]2</u>

Explanation:

2H2S(g)⇋2H2(g)+S2(g)2H2S(g)⇋2H2(g)+S2(g)

The equilibrium constant expression in terms of concentrations is:

Kc=<u>[H2]2[S2][H2S]2Kc=[H2]2[S2][H2S]2</u><u>.</u>

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7 0
2 years ago
Which of the following is true?
Tomtit [17]

Answer:

a. A reaction in which the entropy of the system increases can be spontaneous only if it is endothermic.

Explanation:

The change in free energy (ΔG) that is, the <u>energy available to do work</u>, of a system for a constant-temperature process is:

ΔG = ΔH - TΔS

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  • When ΔG = 0 the system is at equilibrium.

If <u>both ΔH and ΔS are positive</u>, then ΔG will be negative only when the TΔS  term is greater in magnitude than ΔH. This condition is met when T is large.

3 0
2 years ago
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One mole of water weighs 18 grams. H₂O is composed of 2H= 2 and 1 0=16 adding gives you 18. number of moles= mass/ Relative Molecular Mass

Therefore, mass= Relative Molecular Mass×number of moles

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                           = 90 grams

5 0
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