How much heat energy is required to raise the temperature of 20 kilograms of water from 0°C to 35°C?

A volume of saline solution had a mass of 61.4 g at 4°C. An equal volume of water at the same

Maurinko [17]

Multiple by 2 because it was give u right answer

5 0

2 years ago

Which of the following is a double replacement reaction? Ca(OH)2 + H2SO4 → CaSO4 + 2H2O CH4 + 2O2 → CO2 + 2H2O 8Fe + S8 → 8FeS Z

abruzzese [7]

That would be the first option Ca(OH)2 + H2SO4 → CaSO4 + 2H2O.

The Ca replaces the H2 in H2SO4, and the H2 replaces the Ca is Ca(OH)2.

8 0

3 years ago

Read 2 more answers

To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple _______. Then, plot ln(K

Aloiza [94]

Answer:

To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple temperatures. Then, plot ln(Ksp) vs. 1/T. The slope of the plotted line relates to the enthalpy (ΔH) of dissolving and the intercept of the plotted line relates to the entropy (ΔS) of dissolving.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us use the thermodynamic definition of the Gibbs free energy and its relationship with Ksp as follows:

$\Delta G=-RTln(Ksp)\\\\\Delta G=\Delta H-T\Delta S$

Thus, by combining them, we obtain:

$-RTln(Ksp)=\Delta H-T\Delta S\\\\ln(Ksp)=-\frac{\Delta H}{RT} +\frac{T\Delta S}{RT} \\\\ln(Ksp)=-\frac{\Delta H}{RT} +\frac{\Delta S}{R}$

Which is related to the general line equation:

$y=mx+b$

Whereas:

$y=ln(Ksp)\\\\m=-\frac{\Delta H}{R} \\\\x=\frac{1}{T} \\\\b=\frac{\Delta S}{R}$

It means that we answer to the blanks as follows:

To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple temperatures. Then, plot ln(Ksp) vs. 1/T. The slope of the plotted line relates to the enthalpy (ΔH) of dissolving and the intercept of the plotted line relates to the entropy (ΔS) of dissolving.

Regards!

8 0

3 years ago

A weather balloon contains 1.10X10 to the power of 5 mol of helium and has a volume of 2.70x10 to the power of 6 L at 1.00 atm p

olchik [2.2K]

Answer:

299.14 K or 26°C

Explanation:

The ideal gas law, also called the general gas equation, is the equation of state of a hypothetical ideal gas.

The ideal gas law is often written as

PV = nRT

where P ,V and T are the pressure, volume and absolute temperature;

n is the number of moles of gas and R is the ideal gas constant.

n=1.10 x 10^5 mol

V= 2.70 x 10^6 L

P= 1.00 atm= 101.325 kPa

R= 8.314 kPa*L/ mol*K

when the formula is rearranged, T=PV/ nR

T = (101.325kPa * 2.70 x 10^6 L)/ (1.10 x 10^5 mol * 8.314 kPa*L/ mol*K)

T = 299.1421917 K

or

T = 299.14 - 273.15 = 25.99 = 26°C

4 0

3 years ago

How does helium form (5-8) sentences

Firlakuza [10]

On Earth it is relatively rare—5.2 ppm by volume in the atmosphere. Most terrestrial helium<span> present today is created by the natural radioactive decay of heavy radioactive elements (thorium and uranium, although there are other examples), as the alpha particles emitted by such decays consist of </span>helium<span>-4 nuclei.</span>

7 0

3 years ago