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Vesnalui [34]
3 years ago
12

Shape 1 and shape 2 are plotted on a coordinate plane. Which statement about the shapes is true?

Mathematics
2 answers:
jenyasd209 [6]3 years ago
3 0
<span>Following option is correct answer

Shape 1 is not congruent to shape 2 because a sequence of rigid transformations will not map shape 1 onto shape 2.</span>
Maksim231197 [3]3 years ago
3 0

Answer:

D

Step-by-step explanation:

(Michigan online school.)

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Which is the equation of the line that passes through the point (-5, -2)
Lilit [14]

Answer:

F) y=3x+13

Step-by-step explanation:

y-y1=m(x-x1)

y-(-2)=3(x-(-5))

y+2=3(x+5)

y=3x+15-2

y=3x+13

5 0
3 years ago
F(x)=x^4-5x^2-6x-10 is divided by x-3
LiRa [457]

Answer:

Step-by-step explanation:

STEP

1

:

           10

Simplify   ——

           x

Equation at the end of step

1

:

                       10

 ((((x4)-(5•(x2)))-6x)-——)-3

                       x

STEP

2

:

Equation at the end of step

2

:

                           10    

 ((((x4) -  5x2) -  6x) -  ——) -  3

                           x      

STEP

3

:

Rewriting the whole as an Equivalent Fraction

3.1   Subtracting a fraction from a whole

Rewrite the whole as a fraction using  x  as the denominator :

                     x4 - 5x2 - 6x     (x4 - 5x2 - 6x) • x

    x4 - 5x2 - 6x =  —————————————  =  ———————————————————

                           1                    x        

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

STEP

4

:

Pulling out like terms

4.1     Pull out like factors :

  x4 - 5x2 - 6x  =   x • (x3 - 5x - 6)

Polynomial Roots Calculator :

4.2    Find roots (zeroes) of :       F(x) = x3 - 5x - 6

Polynomial Roots Calculator is a set of methods aimed at finding values of  x  for which   F(x)=0  

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers  x  which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number  P/Q   then  P  is a factor of the Trailing Constant and  Q  is a factor of the Leading Coefficient

In this case, the Leading Coefficient is  1  and the Trailing Constant is  -6.

The factor(s) are:

of the Leading Coefficient :  1

of the Trailing Constant :  1 ,2 ,3 ,6

Let us test ....

  P    Q    P/Q    F(P/Q)     Divisor

     -1       1        -1.00        -2.00    

     -2       1        -2.00        -4.00    

     -3       1        -3.00        -18.00    

     -6       1        -6.00        -192.00    

     1       1        1.00        -10.00    

     2       1        2.00        -8.00    

     3       1        3.00        6.00    

     6       1        6.00        180.00    

Polynomial Roots Calculator found no rational roots

Adding fractions that have a common denominator :

4.3       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

x • (x3-5x-6) • x - (10)     x5 - 5x3 - 6x2 - 10

————————————————————————  =  ———————————————————

           x                          x        

Equation at the end of step

4

:

 (x5 - 5x3 - 6x2 - 10)    

 ————————————————————— -  3

           x              

STEP

5

:

Rewriting the whole as an Equivalent Fraction

5.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  x  as the denominator :

        3     3 • x

   3 =  —  =  —————

        1       x  

Checking for a perfect cube :

5.2    x5 - 5x3 - 6x2 - 10  is not a perfect cube

Trying to factor by pulling out :

5.3      Factoring:  x5 - 5x3 - 6x2 - 10

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  -6x2 - 10

Group 2:  x5 - 5x3

Pull out from each group separately :

Group 1:   (3x2 + 5) • (-2)

Group 2:   (x2 - 5) • (x3)

Bad news !! Factoring by pulling out fails :

The groups have no common factor and can not be added up to form a multiplication.

Polynomial Roots Calculator :

5.4    Find roots (zeroes) of :       F(x) = x5 - 5x3 - 6x2 - 10

    See theory in step 4.2

In this case, the Leading Coefficient is  1  and the Trailing Constant is  -10.

The factor(s) are:

of the Leading Coefficient :  1

of the Trailing Constant :  1 ,2 ,5 ,10

Let us test ....

  P    Q    P/Q    F(P/Q)     Divisor

     -1       1        -1.00        -12.00    

     -2       1        -2.00        -26.00    

     -5       1        -5.00       -2660.00    

     -10       1       -10.00       -95610.00    

     1       1        1.00        -20.00    

     2       1        2.00        -42.00    

     5       1        5.00        2340.00    

     10       1        10.00       94390.00    

Polynomial Roots Calculator found no rational roots

Adding fractions that have a common denominator :

5.5       Adding up the two equivalent fractions

(x5-5x3-6x2-10) - (3 • x)      x5 - 5x3 - 6x2 - 3x - 10

—————————————————————————  =  ————————————————————————

            x                            x            

Polynomial Roots Calculator :

5.6    Find roots (zeroes) of :       F(x) = x5 - 5x3 - 6x2 - 3x - 10

    See theory in step 4.2

In this case, the Leading Coefficient is  1  and the Trailing Constant is  -10.

The factor(s) are:

of the Leading Coefficient :  1

of the Trailing Constant :  1 ,2 ,5 ,10

Let us test ....

  P    Q    P/Q    F(P/Q)     Divisor

     -1       1        -1.00        -9.00    

     -2       1        -2.00        -20.00    

     -5       1        -5.00       -2645.00    

     -10       1       -10.00       -95580.00    

     1       1        1.00        -23.00    

     2       1        2.00        -48.00    

     5       1        5.00        2325.00    

     10       1        10.00       94360.00    

Polynomial Roots Calculator found no rational roots

Final result :

 x5 - 5x3 - 6x2 - 3x - 10

 ————————————————————————

            x            

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3 years ago
If, for all x, f'(x)=(x-2)^4(x-1)^3, it follows that funtaion f has
Elenna [48]

Answer:

We say that f(x) has an absolute (or global) minimum at x=c if f(x)≥f(c) f ( x ) ≥ f ( c ) for every x in the domain we are working on. We say that f(x) has a relative (or local) minimum at x=c iff(x)≥f(c) f ( x ) ≥ f ( c ) for every x in some open interval around x=c .

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Answer:

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Step-by-step explanation:

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