Which type of construction is used to construct a triangles point of balance?
1 answer:
You might be interested in
We know that
the equation of a line in <span>slope intercept form is--------------> y=mx+b
where
m-----------> is the slope
b-----------> is the y-intercept point when x=0
</span><span>y+7=-1/7(x+4)---------> y+7=(-1/7)x-4/7
</span>y+7=(-1/7)x-4/7------> y=(-1/7)x-4/7-7------> y=(-1/7)x-(53/7)
the answer is
y=(-1/7)x-(53/7)-------------> this is the equation of a line in slope intercept form
m=(-1/7)=-0.14
b=(-53/7)=-7.57
y=-0.14x-7.57
see the attached figure
the equation of a line in <span>slope intercept form is--------------> y=mx+b
where
m-----------> is the slope
b-----------> is the y-intercept point when x=0
</span><span>y+7=-1/7(x+4)---------> y+7=(-1/7)x-4/7
</span>y+7=(-1/7)x-4/7------> y=(-1/7)x-4/7-7------> y=(-1/7)x-(53/7)
the answer is
y=(-1/7)x-(53/7)-------------> this is the equation of a line in slope intercept form
m=(-1/7)=-0.14
b=(-53/7)=-7.57
y=-0.14x-7.57
see the attached figure