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alisha [4.7K]
3 years ago
14

True or false? Causation statement The more you pay for a house makes you spend more for a car

Mathematics
1 answer:
liberstina [14]3 years ago
5 0

Answer:

false

Step-by-step explanation:

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If a polygon is a pentagon, then it has 5 sides hypothesis conclusion
quester [9]

Answer:

Hypothesis

 

Step-by-step explanation:

 a polygon has five sides Conclusion: it is a pentagon If a polygon has five sides, then it is a pentagon.

hope this helps

8 0
3 years ago
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a taxi cost $1.65 for the 1st Mile and $0.85 for each additional mile. Which equation could be solved to find the number x of ad
Gekata [30.6K]
X = additional mile

0.85x + 1.65 = 20

to solve it:
subtract 1.65 from both sides. afterwards, divide both sides by 0.85 to find x!
7 0
3 years ago
Jay has 195 baseball cards, Jen has 46 more than Jay, how many more cards does Jen have than Jay? (I will give brainliest)
bogdanovich [222]
Jen has 46 more than Jay, “Jen has 46 more than Jay.” You answered your own question.
6 0
2 years ago
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Favorite radio station has this hourly
IceJOKER [234]
P(n)=news time/total time 

We are told that the news is 14 minutes long during an hour so

p(n)=14/60

p(n)=7/30
7 0
3 years ago
For what value of c is the function defined below continuous on (-\infty,\infty)?
kozerog [31]
f(x)= \left \{ {{x^2-c^2,x \ \textless \  4} \atop {cx+20},x \geq 4} \right


It's clear that for x not equal to 4 this function is continuous. So the only question is what happens at 4.
<span>A function, f, is continuous at x = 4 if 
</span><span>\lim_{x \rightarrow 4} \  f(x) = f(4)

</span><span>In notation we write respectively
</span>\lim_{x \rightarrow 4-} f(x) \ \ \ \text{ and } \ \ \ \lim_{x \rightarrow 4+} f(x)

Now the second of these is easy, because for x > 4, f(x) = cx + 20. Hence limit as x --> 4+ (i.e., from above, from the right) of f(x) is just <span>4c + 20.
</span>
On the other hand, for x < 4, f(x) = x^2 - c^2. Hence 
\lim_{x \rightarrow 4-} f(x) = \lim_{x \rightarrow 4-} (x^2 - c^2) = 16 - c^2

Thus these two limits, the one from above and below are equal if and only if
 4c + 20 = 16 - c²<span> 
 Or in other words, the limit as x --> 4 of f(x) exists if and only if
 4c + 20 = 16 - c</span>²

c^2+4c+4=0&#10;\\(c+2)^2=0&#10;\\c=-2

That is to say, if c = -2, f(x) is continuous at x = 4. 

Because f is continuous for all over values of x, it now follows that f is continuous for all real nubmers (-\infty, +\infty)

4 0
3 years ago
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