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3 years ago

Two parallel lines are crossed by a transversal

Mathematics

2 answers:

Rainbow [258]3 years ago

3 0

Ans x95

Step-by-step explanation:

Black_prince [1.1K]3 years ago

3 0

Answer:

x=115

Step-by-step explanation:

on the test

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the russian ice breaker Yamal can move forward through 2.3 meter 2.3 meter thick ice at a speed 5.5 kilometers

morpeh [17]

Answer:

Yamal can move the ice to 82 km in approximately <u>15 hrs</u>.

Step-by-step explanation:

Given:

Speed = 5.5 km/hr

Distance = 82 km

Let time be represented as 'x'.

We need to find the number of hours required to travel 82 km.

We know that Distance can be calculated by the product of Speed and time.

Framing above sentence in equation form we get;

Distance = Speed × Time

Substituting the given value we get;

$82 = 5.5x$

Hence The expression for number of hours is $82 = 5.5x$

Solving the equation to find the value of x we get;

$82 = 5.5x\\\\x=\frac{82}{5.5} = 14.90 \approx 15\ hrs$

Hence Yamal can move the ice to 82 km in approximately <u>15 hrs</u>.

3 0

3 years ago

Simplify 6⁢(3⁢x - 5) + 5⁢(2⁢x - 1).

tatuchka [14]

Answer:

28x-35

Step-by-step explanation:

5 0

3 years ago

How to simplify ( 2/4)^2

Otrada [13]

Answer:

2/4x2/4=0.25 or 1/4

Step-by-step explanation:

4 0

3 years ago

Sebastian is drawing a map of his local park. The actual park is a rectangle that is 300 feet long and 240 feet wide. Sebastian

12345 [234]

The ratio of the park's length and width is 300/240=5/4
if he takes the length as 10in then the width should be 8in,
so it's area should be 80in²

5 0

3 years ago

What is a11. A12. A21. A22

Ierofanga [76]

Answer:

$a_{11} =-1\\a_{12} =3\\a_{21} =5\\a_{22} =3/2\\$

Step-by-step explanation:

$2X-\left[\begin{array}{ccc}-4&8\\2&-2\end{array}\right] =\left[\begin{array}{ccc}2&-2\\8&5\end{array}\right]\\X=\frac{1}{2} (\left[\begin{array}{ccc}-4&8\\2&-2\end{array}\right] +\left[\begin{array}{ccc}2&-2\\8&5\end{array}\right])\\X=\frac{1}{2} (\left[\begin{array}{ccc}-4+2&8-2\\2+8&-2+5\end{array}\right] )\\X=\frac{1}{2} (\left[\begin{array}{ccc}-2&6\\10&3\end{array}\right] )\\X= (\left[\begin{array}{ccc}\frac{1}{2}(-2)&\frac{1}{2}(6)\\\frac{1}{2}(10)&\frac{1}{2}(3)\end{array}\right] )\\$

$X= (\left[\begin{array}{ccc}-1&3\\5&3/2\end{array}\right] )$

$a_{11} =-1\\a_{12} =3\\a_{21} =5\\a_{22} =3/2\\$

8 0

3 years ago