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djyliett [7]
3 years ago
6

5

Mathematics
1 answer:
Furkat [3]3 years ago
3 0

Answer:

I hope it is correct.....

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Find the x-values that are solutions of the equation 5cot^2x-15=0
julia-pushkina [17]
First solve for the trig function 'cot'
cot^2 x = \frac{15}{5} = 3

Next take the sqrt of both sides (include plus/minus)
cot x = \pm \sqrt{3}

Now take reciprocal of both sides, this will change trig function to 'tan'
(cot = 1/tan)

tan x = \pm \frac{1}{\sqrt{3}} = \pm \frac{\sqrt{3}}{3}

Finally use the unit circle or inverse tan on your calculator to find x.
There will be 4 solutions, one for each quadrant.

x = \frac{\pi}{6}, \frac{5\pi}{6}, \frac{7\pi}{6}, \frac{11\pi}{6}
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