Ie 32^2 - 4ac=0 so ac=256 and a+c=130
So, that means:2 equations ac=256 a+c=130 ie c=130-a
So,a(130-a)=256 so 130a -a^2=256 ie a^2-130a +256=0 (a-2)(a-128)=0
Finally,giving a= 2 or a=128 so, a=2 c=128 or a=128 c=2
Since, a>c , a=128 and c=2 ie (128,2)
Answer:
18
Step-by-step explanation:
q^2 - 5q +4
Let q = -2
(-2)^2 - 5(-2) +4
4 + 10 +4
18
Answer:yk i’m looking for the answer too, i can’t find it
Step-by-step explanation:
Given:
The inequality is:

To find:
The domain and range of the given inequality.
Solution:
We have,

The related equation is:

This equation is defined if:


In the given inequality, the sign of inequality is <, it means the points on the boundary line are not included in the solution set. Thus, -3 is not included in the domain.
So, the domain of the given inequality is x>-3.
We know that,



The points on the boundary line are not included in the solution set. Thus, 1 is not included in the range.
So, the domain of the given inequality is y>1.
Therefore, the correct option is A.
Answer:
10
Step-by-step explanation:
20 - 10 = 10