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I am Lyosha [343]
3 years ago
11

Mr. Itol's assistant takes twice as long to complete a computer task as Mr. Itol. If it takes both experts 6 hours to complete t

he task, how long will it take each of them to do the job alone?
Mathematics
1 answer:
Lesechka [4]3 years ago
4 0
So, in order to solve this problem, I will set up an equation. First, let's make x= the # of hours it takes Mr. Itol to complete a computer task, and since his assistant takes twice as long, lets make 2x=the # of hours it takes the assistant to complete the task. We also know that it takes the two of them 6 hours to complete the task together. We can now set up the following equation: 

\frac{1}{2x} +  \frac{1}{x} =  \frac{1}{6}

Now, in order to be able to solve this, we have to find the least common denominator, and then we can cancel out the denominators to solve for the top part. The LCD=6x and the new equation becomes: 

\frac{3}{6x} +  \frac{6}{6x} =  \frac{x}{6x}

Now, we can get rid of the denominators, and we get:

3+6=x

So, x= 9

Now we know that Mr. Itol would take 9 hours to complete the task if he were to do it himself. To find how long it would take his assistant to complete the same task by himself, we just need to plug in the x-value into 2x:

2(9)=18

Therefore, your answer is that Mr. Itol would take 9 hours to do the job alone, while his assistant will take 18 hours (double the time) to do the job alone.

Hope this helps :) 










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Of all the weld failures in a certain assembly, 85% of them occur in the weld metal itself, and the remaining 15% occur in the b
Aloiza [94]

Answer:

a.) 0.1028

b.) 0.6477

c.) 0.0388

d.) 3

e.) 2.55

Step-by-step explanation:

Forming a binomial Probability distribution

n = 20

Probability of success for Weld metal failure = 85%

Probability of success for base metal failure = 15%

We use the probabilit distribution formula of combination to solve the problem.

P(x=r) = nCr * p^r * q^n-r

a.) if exactly 5 are base metal failures, then p = 15 and our solution becomes:

P(x=5) = 20C5 * 0.15^5 * 0.85^15

P(x=5) = 0.1028

b.) probability that fewer than 4 are base metal failure= P(x=0) + P(x=1) + P(x=2) + P(x=3)

P(x=0) = 20C0 * 0.15^0 * 0.85^20 = 0.0388

P(x=1) = 20C1 * 0.15¹ * 0.85^19 = 0.1368

P(x=2) = 20C2 * 0.15² * 0.85^18 = 0.2293

P(x=3) = 20C3 * 0.15³ * 0.85^17 = 0.2428

Probability that fewer than 4 are base metal failures becomes: 0.038 + 0.1368 + 0.2293 + 0.2428 = 0.6477

c.) probability that none of them are results of base metal failure = P(x=0). As earlier calculated,

P(x=0) = 0.0388

d.) mean of base metal failures = np = 20*0.15 = 3

e.) standard deviation of base metal failures = √np(1-p)

=3 * (1 - 0.15) = 3 * 0.85

= 2.55

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Answer:

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Find the distance between the points (<br> -<br> 10,12) and (15,12).
Nitella [24]
The distance formula is:

d= \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}

We are given two points in the form (x,y), so plug in the values to the distance formula:

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The square and square root cancel each other out leaving us with 25.

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