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finlep [7]
3 years ago
9

Is Y=10x proportional

Mathematics
1 answer:
solmaris [256]3 years ago
5 0

Answer:

yes

Step-by-step explanation:

The standard form of a proportional equation is

y = kx ← k is the constant of proportionality

y = 10x ← is in this form and represents proportion.

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Which ordered pair is the best estimate for the solution of the system of equations?
stiks02 [169]
The graph shows the solution to be (7, 0.5).

The 2nd selection is appropriate.

8 0
3 years ago
Simplify c + 6 < -20
Stels [109]

Answer:

Step-by-step explanation:

c + 6 < -20

Subtract 6 from both side

c +6 -6 < -20-6

c < -26

So value of c should be less than -26. Value of c = { - ∞ ...... -28, - 27 }

Eg:

If c = -27

-27 + 6 = - 21 . -21 is less than -20

7 0
4 years ago
Since 1970, the # (in thousands) of males M and females F attending institutes of higher education can be modeled by: M=0.091t^3
lilavasa [31]
Can you make this clearer so i can understand
3 0
4 years ago
The point A(4, 1) is reflected over the point (0, -3) and its image is point B. What are the coordinates of point B?
omeli [17]

A reflection over the point (0,0) is given by:

(x,y)\rightarrow(-x,-y)

Nevertheless, the reflection is being made over the point (0,-3). We can first make a traslation of the point (0,-3) to the origin. Then, reflect the new coordinates of the point A through the origin and then bring back the new origin to (0,-3).

First, make a traslation such that the new coordinates of (0,-3) are (0,0):

(x,y)\rightarrow(x,y+3)

Then, apply a reflection through the origin:

(x,y+3)\rightarrow(-x,-y-3)

Finally, make a traslation reciprocal to the first one:

(-x,-y-3)\rightarrow(-x,-y-3-3)=(-x,-y-6)

Therefore, the reflection over the point (0,-3) can be written as:

(x,y)\rightarrow(-x,-y-6)

Substitute (x,y)=(4,1) to find out the new coordinates of A after the reflection:

\begin{gathered} A\rightarrow B \\ \Rightarrow(4,1)\rightarrow(-4,-1-6)=(-4,-7) \end{gathered}

Therefore, the coordinates of the point B are (-4,-7).

4 0
1 year ago
The sum of two positive integers, x and y, is not more than 40. The difference of the two integers is at least 20. Chaneece choo
oksian1 [2.3K]
<span>Chaneece chooses x as the larger number and uses the inequalities y ≤ 40 – x and y ≤ x – 20 to determine the possible solutions.

</span>y ≤ 40 – x, if x must be between 0 and 10, y must be between 20 and 40 <span>it is true
proof
</span><span>for x=0  and y=10,  y ≤ 40 – x equivalent to 10<40-0=40 it is true
</span>x=10, y=30,   <span>y ≤ 40 – x  equivalent to 30=40-10=30 it is true

the answer is </span><span>A) Yes, Chaneece found the correct solution. </span>
5 0
3 years ago
Read 2 more answers
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