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Sunny_sXe [5.5K]
2 years ago
5

I’m so lost. which username do i do.

Computers and Technology
2 answers:
koban [17]2 years ago
5 0

Answer:

the username you feel like using

Mrac [35]2 years ago
5 0
Um I don’t get this question and what’s on the photo ?
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Write the following arithmetic expression as a valid C arithmetic expression: x = x + number
otez555 [7]

Answer:

x = x + number

x+=number

Explanation:

Given

x = x + number

Required

Write an equivalent expression in C

The given expression uses + and + is represented as + in C

So: The equivalent expression is

x = x + number

However, C supports compound assignment operators

So:

x = x + number

can be rewritten as

x+=number

3 0
3 years ago
Outside of a C program, a file is identified by its ________while inside a C program, a file is identified by a(n) ________. fil
Alexxandr [17]

Answer: name, file stream object

Explanation:

4 0
2 years ago
A biologic reaction is produced by 4 Gyt of a test radiation. It takes 16 Gyt of 250-kVp x-rays to produce the same biologic rea
Shalnov [3]

Answer:

4

Explanation:

Relative Biological Effectiveness (RBE) =

Standard Radiation dose / Test Radiation dose

for achieving the same biological effect.

The absorbed radiation dose is measured in units of Gyt(Gray in tissue).

In the given scenario, Standard radiation dose of 250 KVp X-rays = 16 Gyt

Corresponding Test Radiation dose = 4 Gyt

Therefore, Relative Biological Effectiveness = 16/4 = 4

7 0
3 years ago
At one college, the tuition for a full-time student is $6,000 per semester. It has been announced that the tuition will increase
Alina [70]

Answer:

  1. var projected_fee = 6000;  
  2. for(var i = 1; i <= 5; i++){
  3.    projected_fee = projected_fee * 0.02 + projected_fee;
  4.    console.log("$" + projected_fee.toFixed(2));
  5. }

Explanation:

Firstly, create a variable, projected_fee, and set the initial tuition fee value to it (Line 1).

Next, user a for loop that run for 5 times to repeatedly calculate the projected_fee based on 2 percent of increment rate (Line 4) and display the projected fee to console terminal (Line 5). The output should be

$6120.00

$6242.40

$6367.25

$6494.59

$6624.48

8 0
3 years ago
Write a procedure named Str_find that searches for the first matching occurrence of a source string inside a target string and r
kirill115 [55]

Answer: Provided in the explanation section

Explanation:

Str_find PROTO, pTarget:PTR BYTE, pSource:PTR BYTE

.data

target BYTE "01ABAAAAAABABCC45ABC9012",0

source BYTE "AAABA",0

str1 BYTE "Source string found at position ",0

str2 BYTE " in Target string (counting from zero).",0Ah,0Ah,0Dh,0

str3 BYTE "Unable to find Source string in Target string.",0Ah,0Ah,0Dh,0

stop DWORD ?

lenTarget DWORD ?

lenSource DWORD ?

position DWORD ?

.code

main PROC

  INVOKE Str_find,ADDR target, ADDR source

  mov position,eax

  jz wasfound           ; ZF=1 indicates string found

  mov edx,OFFSET str3   ; string not found

  call WriteString

  jmp   quit

wasfound:                   ; display message

  mov edx,OFFSET str1

  call WriteString

  mov eax,position       ; write position value

  call WriteDec

  mov edx,OFFSET str2

  call WriteString

quit:

  exit

main ENDP

;--------------------------------------------------------

Str_find PROC, pTarget:PTR BYTE, ;PTR to Target string

pSource:PTR BYTE ;PTR to Source string

;

; Searches for the first matching occurrence of a source

; string inside a target string.

; Receives: pointer to the source string and a pointer

;    to the target string.

; Returns: If a match is found, ZF=1 and EAX points to

; the offset of the match in the target string.

; IF ZF=0, no match was found.

;--------------------------------------------------------

  INVOKE Str_length,pTarget   ; get length of target

  mov lenTarget,eax

  INVOKE Str_length,pSource   ; get length of source

  mov lenSource,eax

  mov edi,OFFSET target       ; point to target

  mov esi,OFFSET source       ; point to source

; Compute place in target to stop search

  mov eax,edi    ; stop = (offset target)

  add eax,lenTarget    ; + (length of target)

  sub eax,lenSource    ; - (length of source)

  inc eax    ; + 1

  mov stop,eax           ; save the stopping position

; Compare source string to current target

  cld

  mov ecx,lenSource    ; length of source string

L1:

  pushad

  repe cmpsb           ; compare all bytes

  popad

  je found           ; if found, exit now

  inc edi               ; move to next target position

  cmp edi,stop           ; has EDI reached stop position?

  jae notfound           ; yes: exit

  jmp L1               ; not: continue loop

notfound:                   ; string not found

  or eax,1           ; ZF=0 indicates failure

  jmp done

found:                   ; string found

  mov eax,edi           ; compute position in target of find

  sub eax,pTarget

  cmp eax,eax    ; ZF=1 indicates success

done:

  ret

Str_find ENDP

END main

cheers i hoped this helped !!

6 0
3 years ago
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