A package of aluminum foil is 59.3 yd long, 13 in. wide, and 0.00040 in. thick. If aluminum has a density of 2.70 g/cm3, what is
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Answer: An archer pulls her bowstring back 0.400m by exerting a force that increases uniformly from zero to 230N. The equivalent spring constant of the bow will be 575N/m
Explanation: To find the answer, we have to know about the Simple Harmonic Motion.
<h3>What is Simple Harmonic Motion?</h3>- A particle is said to execute simple harmonic motion, if it moves to and fro about mean position under the action of restoring force.
- The restoring force is directly proportional to its displacement from the mean position and always directed towards the mean position.
- If x is the displacement from the mean position, and F is the restoring force, then
∝
where, k is called the spring constant.
- Given that, an archer pulls her bowstring back 0.400m by exerting a force that increasing from zero to 230N.
- Here, from the question given, we can write,
and
.
- Thus, our spring constant k will be,
Thus, we can conclude that, the equivalent spring constant of the bow will be 575N/m.
Learn more about the Simple Harmonic Motion here:
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