Answer:
493.02 g.
Explanation:
Density = mass/volume
mass = density×volume
m = D×V ............................ Equation 1
m = mass of the aluminum foil, D = Density of the aluminum foil, V = volume of the aluminum foil.
V = L×W×H................... Equation 2
Where L = length of the aluminum foil, W = wide of the aluminum foil, H = thickness of the aluminum foil.
Given: L = 59.3 yd = 59.3×0.9144 m = 54.224 m, W = 13 in = 13×0.0254 m = 0.3302 m, H = 0.00040 in = 0.00040×0.0254 m = 0.0000102 m.
Substituting into equation 2
V = 54.224×0.3302×0.0000102
V = 0.0001826 m³ = (0.0001826×1000000) cm³
V = 182.6 cm³
Also given D = 2.70 g/cm³
Substitute into equation 1
m = 2.7×182.6
m = 493.02 g.
The mass in grams of the foil = 493.02 g.
