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Answer:
The magnitude of the magnetic field is 1.01T and its direction is in the negative x direction
Explanation:
In order to calculate the magnitude and direction of the magnetic field, you take into account the following equation for the magnetic force on the proton:
(1)
v: speed of the proton = 9.9*10^5 m/s
q: charge of the proton = 1.6*10^-19C
B: magnetic field = ?
FB: magnetic force on the proton = 1.6*10^-13N
When the proton travels in the positive y direction (^j), you have that the proton experiences a force in the positive z direction (+^k). To obtain this direction of the magnetic force on the proton, it is necessary that the magnetic field points in the negative x direction, in fact, you have:
^j X (-^i) = -(-^k)=^k
To obtain the magnitude of the magnetic field you use:
The magnitude of the magnetic field is 1.01T and its direction is in the negative x direction
Answer:
Normal force, = 707 N
Given:
Mass of the rider, M = 72.1 kg
acceleration due ti gravity, g = 9.8 m/
Velocity of the elevator is constant
Solution:
Since, the elevator is moving with a constant velocity, therefore, the frame we are dealing with is an inertial frame and will not allow any pseudo force to act on it.
The Normal force, N will now be equal to the weight, W of the body which is the product of its mass and the acceleration acting on the body due to gravity and is given by:
= W =
putting the values in the above formula
=
= 707 N (approx)