Answer:
The resultant force would (still) be zero.
Explanation:
Before the 600-N force is removed, the crate is not moving (relative to the surface.) Its velocity would be zero. Since its velocity isn't changing, its acceleration would also be zero.
In effect, the 600-N force to the left and 200-N force to the right combines and acts like a 400-N force to the left.
By Newton's Second Law, the resultant force on the crate would be zero. As a result, friction (the only other horizontal force on the crate) should balance that 400-N force. In this case, the friction should act in the opposite direction with a size of 400 N.
When the 600-N force is removed, there would only be two horizontal forces on the crate: the 200-N force to the right, and friction. The maximum friction possible must be at least 200 N such that the resultant force would still be zero. In this case, the static friction coefficient isn't known. As a result, it won't be possible to find the exact value of the maximum friction on the crate.
However, recall that before the 600-N force is removed, the friction on the crate is 400 N. The normal force on the crate (which is in the vertical direction) did not change. As a result, one can hence be assured that the maximum friction would be at least 400 N. That's sufficient for balancing the 200-N force to the right. Hence, the resultant force on the crate would still be zero, and the crate won't move.
Well YOU cant make your questions verified. if theres more than one answer to the question the person who asked the question will choose the best answer. usually based upon like how well it explains and if its the right answer
4.096. You just have to multiply 1.6 three times. V=s^3
Answer:
24.4 m
Explanation:
first we have to calculate how long the cat will be in the air, in vertical direction this is free fall from 4m (poor cat, hope he survived) with acceleration of g=9.81 m/s^2
time = sqrt ( 2 * height / g)
time = sqrt (2 * 4 / 9.81)
time = 0,903 s
then we know his horizontal flight was 22 m long, so ve can calculate verical speed
speed = length / time
speed = 22 m / 0,903 s
speed = 24.363 m
as you are asked to give 3 significant numbers answer is 24,4 m
