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Tamiku [17]
3 years ago
11

If the voltage across the first capacitor (the one with capacitance

Physics
1 answer:
RoseWind [281]3 years ago
8 0
The answer to this question is: it depends. It depends on the arrangement of the capacitors in a circuit: it can be either in series or in parallel. The difference is shown in the picture. 

Capacitors are like batteries in a way that they store power from the source. It has some rules depending on the type of circuit. For parallel circuits, the voltage across each capacitor is equal. Therefore, V₁=V₂=V₃.

On the other hand, if the capacitors are arranged in series, the voltage across each capacitor should add up to the total voltage of the source. Therefore, V₁+V₂+V₃ = Total Voltage.


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voltage across 2.0μf capacitor is 5.32v

Given:

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since two capacitors are in series there equivalent capacitance will be

[tex] \frac{1}{c} = \frac{1}{c1} + \frac{1}{c2} [/tex]

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As the capacitance of a capacitor is equal to the ratio of the stored charge to the potential difference across its plates, giving: C = Q/V, thus V = Q/C as Q is constant across all series connected capacitors, therefore the individual voltage drops across each capacitor is determined by its its capacitance value.

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= 1.33 \times 10 {}^{ - 6}  \times 8

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charge on 2.0μf capacitor is

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learn more about series capacitance from here: brainly.com/question/28166078

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