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3 years ago

An expression is shown below (x^4/3)(x^2/3)

Mathematics

2 answers:

Nitella [24]3 years ago

7 0

$( x^\frac{4}{3}) (x^ \frac{2}{3}) = x^{ \frac{4}{3} + \frac{2}{3} }= x ^\frac{6}{3} = x^2$

Crank3 years ago

4 0

(x^4/3)(x^2/3) =

When you multiply powers with the same base, write the ame base and add the exponents.
Here the common base is x. The exponents are 4/3 and 2/3. The exponents are added.

= x^(4/3 + 2/3)

= x^(6/3)

= x^2

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a photograph is printed in the center of a piece of paper measuring 7 cm by (x + 8) cm. The photo measures 5 cm by (x +6) cm . T

Nadusha1986 [10]

The paper is 7 cm by (x + 8) cm.

A photo is 5 cm by (x + 6) cm, and is printed in the middle of the paper.

The area of the border/space around the photo is 50 cm².

To find the area of the border around the photo, you find the area of the paper and subtract it by the area of the photo.

The area of the paper:

A = 7 · (x + 8)

The area of the photo:

A = 5 · (x + 6)

Your equation to find the area of the border around the photo is:

(7 · (x + 8)) - (5 · (x + 6)) = A

[area of paper - area of photo = area of border]

Since you know the area of the border, you can plug it in:

(7 · (x + 8)) - (5 · (x + 6)) = 50

Multiply the 7 into (x + 8), and multiply the 5 into (x + 6)

(7x + 56) - (5x + 30) = 50

Distribute/multiply the - to (5x + 30)

7x + 56 - 5x - 30 = 50

Combine like terms

2x + 26 = 50

Subtract 26 on both sides

2x = 24

Divide 2 on both sides

x = 12

7 0

3 years ago

A sales team estimates that the number of new phones they will sell is a function of the price that they set. They estimate that

USPshnik [31]

Answer:

$204

Step-by-step explanation:

The question is at what price x will the company maximize revenue.

The revenue function is:

$R(x) = 4,080x-10x^2$

The price for which the derivate of the revenue function is zero is the price the maximizes revenue:

$R(x) = 4,080x-10x^2\\\frac{dR(x)}{dx}=0=4,080-20x\\x=\frac{4,080}{20}\\ x=\$204$

The company will maximize its revenue when the price is $204.

7 0

3 years ago

A baby bird jumps from a tree branch and flutters to the ground. The function "f" models the bird's height (in meters) above the

AURORKA [14]

The answer to this question will depend on the function f itself. Basically you will find the height in meters above the ground of the bird when it jumped when the time t=0s. This is substsitute every t in the function for a value of zero and that way you will get the bird's height at the time it jumped. If you were given a graph for this function, you can find the y-intercept of the graph and that will be the answer as well. The question could be written like this:

A baby bird jumps from a tree branch and flutters to the ground. The function " $f(t)-4.9t^{2}+25$ " models the bird's height (in meters) above the ground as a function of time (in seconds) after jumping. What is bird's height above the ground when it jumped.

Answer:

25m

Step-by-step explanation:

Once your function is given, you can substitute t=0 since 0s is the time measured at the moment the bird jumped. So our function will be:

$f(0)=-4.9(0)^2+25$

$f(0)=25m$

So the height of the bird above the ground when it jumped is 25m in this particular function.

8 0

3 years ago

Which of the following equations has only one solution?

leva [86]

Answer:

none

Step-by-step explanation:

5 0

3 years ago

Qual o valor que Z assume? -Cz+ 6z = Tz+ 83

o-na [289]

Answer:

$\large \boxed{z = \dfrac{83}{6 - C - T}}$

Step-by-step explanation:

$\begin{array}{rccl}-Cz + 6z & = & Tz + 83 & \\6z -Cz - Tz &= & 83 & \text{Subtracted Tz from each side}\\z(6 - C - T) & = & 83 & \text{Removed the common factor}\\z& = & \mathbf{\dfrac{83}{6 - C - T}} &\text{Divided each side by 6 - C - T}\\\end{array}\\\\\large \boxed{\mathbf{z = \dfrac{83}{6 - C - T}}}$

3 0

3 years ago