Answer:
1,100,000
Step-by-step explanation:
20000 + 22(20000) + 32 (20000)= 55 (20000)= 1,100,000
A because radius is half of the diameter
Let us make a list of all the details we have
We are given
The cost of each solid chocolate truffle = s
The cost of each cream centre chocolate truffle = c
The cos to each chocolate truffle with nuts = n
The first type of sweet box that contains 5 each of the three types of chocolate truffle costs $41.25
That is 5s+5c+5n = 41.25 (cost of each type of truffle multiplied by their respective costs and all added together)
The second type of sweet box that contains 10 solid chocolate trufles, 5 cream centre truffles and 10 chocolate truffles with nuts cost $68.75
That is 10s+5c+10n = $68.75
The third type of sweet box that contains 24 truffles evenly divided that is 12 each of solid chocolate truffle and chocolate truffle with nuts cost $66.00
That is 12s+12n=$66.00
Hence option C is the right set of equations that will help us solve the values of each chocolate truffle.
Answer:
She applied the exponent -2 to 4(-2) instead of applying the exponent to just -2.
Step-by-step explanation:
i got my rerecord from my flash cards my teacher made of some answers
If tan x = .56, then cot x is 1.79
