Answer:
33.3 cM
Explanation:
Parent 1: blue shell, long antenna : BBLL
Parent 2: green shell, short antenna : bbll
BBLL X bbll :
F1 : BbLl ( blue shell, long antenna )
BbLl X bbll :
BL/bl = 82 : Parental
bl/bl = 78 : Parental
Bl/bl = 37 : Recombinant
bL/bl = 43 : Recombinant
Total = 240
Recombination frequency = (Number of recombinants/ Total offspring)*100
= (80/240) * 100 = 33.33 %
Map distance = recombination frequency
Hence, map distance = 33.3 cM
Answer:
Human diploid cells have 23 pairs of chromosomes. Because of independent assortment during meiosis I, there are 223, or 8.4 million possible gametes that may be created even if crossing over didn't occur.
<span>Mitochondriom is the awnser
</span>
Identical offspring, no formation of gametes, requires only one parent individual to reproduce
It should have four significant figures
