Answer:
Step-by-step explanation:
We can answer this in two ways: Differentiation and Graphing.
<u>Differentitate:</u>
The first derivative of a function yields a function that provides the slope for any point on the line of the original function. The slope of a vertex is zero, so we can set the first derivative to 0 and solve for x.
f(x) = 3(x-1)^2 + 4
f(x) = 3(x-1)(x-1) + 4
f(x) = 3(x^2 - 2x + 1) + 4
f(x) = 3x^2 - 6x + 7
f'(x) = 6x -6
Set this = 0 and find x:
0 = 6x -6
x = 1
The value of y when x=1 in the original equation is:
f(1) = 3(1-1)^2 + 4
y = 4
The vertex is (1,4)
<u>Graph:</u>
You can use DESMOS to plot the function. The result is attached. Look for the vertex and read the coordinates. (1,4) seems to work.
Answer:
A and A
Step-by-step explanation:
please mark brainliest.
Your question is a difference of squares. both terms that need to be factored are squared. to solve take the square root of each put into two terms one of addition and one of subtraction.
anwser= (5x-9)(5x+9)
the reason this works is because when you foil you get
25x²-45x+45x-81
the middle terms cancel revealing
25x²-81
Answer:
1
Step-by-step explanation:
9 goes into 9 once, so 9/9 = 1