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lozanna [386]
4 years ago
5

. Java is a high-level language.. true or false?

Computers and Technology
1 answer:
frutty [35]4 years ago
4 0

Answer:

the answer is true. it is a high level language

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A picture drawn in 3 d is called?​
Varvara68 [4.7K]

Answer:

autostereogram

Explanation:

that^

6 0
3 years ago
Read 2 more answers
The Subset Sum problem is a generalization of the Knapsack problem. Group of answer choices True False g
Katarina [22]

Answer: True

Explanation:

Subset sum problem and Knapsack problem can be solved using dynamic programming.

In case of Knapsack problem there is a set of weights associative with objects and a set of profits associated with each object and a total capacity of knapsack let say C. With the help of dynamic programming we try to include object's weight such that total profit is maximized without fragmenting any weight of objects and without exceeding the capacity of knapsack, it is also called as 0/1 knapsack problem.

Similar to knapsack problem, in subset sum problem there is set of items and a set of weights associated with the items and a capacity let say C, task is to choose the subset of items such that total sum of weights associated with items of subset is maximized without exceeding the total capacity.

On the basis of above statements we can say that subset sum problem is generalization of knapsack problem.

4 0
3 years ago
Write a method that prints on the screen a message stating whether 2 circles touch each other, do not touch each other or inters
beks73 [17]

Answer:

The method is as follows:

public static void checkIntersection(double x1, double y1, double r1, double x2, double y2, double r2){

    double d = Math.sqrt(Math.pow((x1 - x2),2) + Math.pow((y1 - y2),2));

    if(d == r1 + r2){

        System.out.print("The circles touch each other");     }

    else if(d > r1 + r2){

        System.out.print("The circles do not touch each other");     }

    else{

        System.out.print("The circles intersect");     }

}

Explanation:

This defines the method

public static void checkIntersection(double x1, double y1, double r1, double x2, double y2, double r2){

This calculate the distance

    double d = Math.sqrt(Math.pow((x1 - x2),2) + Math.pow((y1 - y2),2));

If the distance equals the sum of both radii, then the circles touch one another

<em>     if(d == r1 + r2){</em>

<em>         System.out.print("The circles touch each other");     }</em>

If the distance is greater than the sum of both radii, then the circles do not touch one another

<em>    else if(d > r1 + r2){</em>

<em>         System.out.print("The circles do not touch each other");     }</em>

If the distance is less than the sum of both radii, then the circles intersect

<em>    else{</em>

<em>         System.out.print("The circles intersect");     }</em>

}

6 0
3 years ago
[20 pts] Write the function rectangle(perimeter, area), which takes two positive integers, perimeter and area. It returns an int
MrRissso [65]

Hi, you haven't provided the programing language in which you need the code, I'll explain how to do it using Python, and you can follow the same logic to make a program in the programing language that you need.

Answer:

import math

def rectangle(perimeter, area):

   l1_1 = (perimeter+math.sqrt((perimeter**2)-(16*area)))/4

   l1_2 = (perimeter-math.sqrt((perimeter**2)-(16*area)))/4

   l2_1 = area/l1_1

   l2_2 = area/l1_2

   print(l1_1,l2_1)

   print(l1_2,l2_2)

   if l1_1.is_integer() and l2_1.is_integer() and l1_1>0 and l2_1>0:

       return(int(max(l1_1,l2_1)))

   elif l1_2.is_integer() and l2_2.is_integer() and l1_2>0 and l2_2>0:

       return(int(max(l1_2,l2_2)))

   else:

       return(None)

Explanation:

  • We import math to make basic operations
  • We define the rectangle function that receives perimeter and area
  • We calculate one of the sides (l1_1) of the rectangle using the quadratic equation to solve 2h^2 - ph + 2a = 0
  • We calculate the second root of the quadratic equation for the same side (l1_2)
  • We calculate the second side of the rectangle using the first root on w = a/h
  • We calculate the second side of the rectangle using the second root on w= a/h
  • We verify that each component of the first result (l1_1, l2_1) is an integer (using the build-in method .is_integer) and greater than 0, if True we return the maximum value between them (using the max function) as w
  • If the first pair of sides evaluate to False we check the second root of the equation and if they meet the specification we return the max value
  • if all the if statements evaluate to false we return None to indicate that not positive or integer sides were found

7 0
3 years ago
Which of the following is considered a benefit of using simulation programs? a. They allow users to experience potentially dange
erica [24]

Answer:

All of the above

Explanation:

7 0
3 years ago
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