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Andreas93 [3]
3 years ago
7

I don't care about getting the answers but rather a step-by-step explanation for this problem: A simple interest, 8-month loan o

f $3,000 has an annual interest rate of 9.3%. Determine the following values. (For the first answer blank, enter an exact number. For the second answer blank, enter a number. For the third answer blank, enter an exact number as an integer, fraction, or decimal.)
P = $

r =

t =


Find the amount of interest paid (in dollars) on this loan. (Enter an exact number.)

I = $


Calculate the maturity value (in dollars) of this loan. (Enter an exact number.)

$
Mathematics
1 answer:
alisha [4.7K]3 years ago
7 0

Answer:

Step-by-step explanation:

The formula for simple interest is expressed as

I = PRT/100

Where

P represents the principal

R represents interest rate

T represents time in years

I = interest after t years

From the information given

T = 8 months = 8/12 = 2/3 years

P = $3000

R = 9.3%

Therefore

I = (3000 × 9.3 × 2/3)/100

I = 18600/100

I = $186

The maturity value (in dollars) of this loan would be

3000 + 186 = $3186

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Answer:

\angle 1 = 45 degrees

Step-by-step explanation:

Sum of 3 angles in a triangle is 180..

The angles given are:

60

7x + 12

1

So we sum to 180 and write:

60+7x+12+\angle 1=180\\72+7x+\angle 1=180\\7x+\angle 1=108

Also, straight angle is 180 degrees, thus Angle 1 and (14x + 9) angle is sum to 180, thus we can write:

14x+9+\angle 1=180\\14x + \angle 1=171

Or we can write this as:

14x + \angle 1=171\\\angle 1 = 171 - 14x

We substitute this expression for Angle 1 into 1st equation we got and solve for x first,

7x+\angle 1 = 108\\7x+( 171 - 14x)=108\\-7x=-63\\x=9

Since x = 9, the angle "14x + 9" would be:

14(9) + 9 = 135

Hence Angle 1 would be:

\angle 1 + 14x + 9 = 180\\\angle 1 + 135 = 180\\\angle 1 = 45

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2 years ago
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Find the derivative.
krek1111 [17]

Answer:

\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}

General Formulas and Concepts:

<u>Algebra I</u>

Terms/Coefficients

  • Expanding/Factoring

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Quotient Rule]:                                                                           \displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle f(x) = \frac{\sqrt{x}}{e^x}

<u>Step 2: Differentiate</u>

  1. Derivative Rule [Quotient Rule]:                                                                   \displaystyle f'(x) = \frac{(\sqrt{x})'e^x - \sqrt{x}(e^x)'}{(e^x)^2}
  2. Basic Power Rule:                                                                                         \displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}(e^x)'}{(e^x)^2}
  3. Exponential Differentiation:                                                                         \displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{(e^x)^2}
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  5. Rewrite:                                                                                                         \displaystyle f'(x) = \bigg( \frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x \bigg) e^{-2x}
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Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

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<h3>Part A:</h3>

The area A of a rectangle is A = bh, where b is the base of the rectangle and h is the height. The area of each rectangle with side lengths 1.5 ft and 2 ft is 1.5 × 2 = 3ft2. Since there are two rectangles with these dimensions, the combined area is 2 × 3 = 6 ft2. The area of each rectangle with side lengths 1.5 ft and 2.5 ft is 1.5 × 2.5 = 3.75 ft2. The area of each rectangle with side lengths 2 ft and 2.5 ft is 2 × 2.5 = 5 ft2. Since there are two rectangles of each type, the combined area is 2 × 3.75 + 2 × 5 =17.5 ft2. <u><em>So, the total surface area of the box is 6 ft2+ 17.5 ft2 = 23.5 ft2</em></u>

<u><em></em></u>

<h3>Part B:</h3>

The employee needs to wrap 8 boxes, each with a surface area of 23.5 ft2. So, the combined surface area needing to be wrapped is 8 × 23.5 = 188 ft2. Since there is only 160 square feet of wrapping paper left, the employee will not be able to wrap all of the gifts

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