In the given table, we can calculate the sample space of the problem. The sample space includes all the categories of the people involved. The sample space is the total of the numbers given. This is equal to 300. The probability ofgetting someone who tests positive, given that he or she had the disease is 141/300 equal to 47 percent
Step-by-step explanation:
h(t) = -5t² + 20t + 18
this is a parabola (the curve an object follows when thrown up into the air and then falling back down).
and as such it will most likely have 2 solutions (one for when going up, and one for when falling back down again).
33 = -5t² + 20t + 18
15 = -5t² + 20t
-3 = t² - 4t
t² - 4t + 3 = 0
the solution of such a quadratic equation is
t = (-b ±sqrt(b² - 4ac))/(2a)
in our case
a = 1
b = -4
c = 3
t = (4 ±sqrt(16 - 4×1×3))/(2×1) = (4 ±sqrt(16-12))/2 =
= (4 ±sqrt(4))/2 = (4 ± 2)/2
t1 = (4+2)/2 = 6/2 = 3
t2 = (4-2)/2 = 2/2 = 1
the object reaches the height of 33 m first after 1 second (while going up), and then again after 3 seconds (while falling down again).
Answer: C
<u>Step-by-step explanation:</u>
1. DOF and GOH are vertical angles 1. Given
2. m∠DOF = m∠GOH 2. Vertical Angles Theorem
3. ∠DOF = 58° 3. Given
4. 58° = m∠GOH 4. Substitution
-16+-x/4=-3
-x/4=13
-x=52
x=-52
