Let
![P(x)=ax^2+bx+c](https://tex.z-dn.net/?f=P%28x%29%3Dax%5E2%2Bbx%2Bc)
. You have derivatives
![P'(x)=2ax+b](https://tex.z-dn.net/?f=P%27%28x%29%3D2ax%2Bb)
and
![P''(x)=2a](https://tex.z-dn.net/?f=P%27%27%28x%29%3D2a)
. Then
![\begin{cases}P(2)=4a+2b+c=5\\P'(2)=4a+b=3\\P''(2)=2a=2\end{cases}](https://tex.z-dn.net/?f=%5Cbegin%7Bcases%7DP%282%29%3D4a%2B2b%2Bc%3D5%5C%5CP%27%282%29%3D4a%2Bb%3D3%5C%5CP%27%27%282%29%3D2a%3D2%5Cend%7Bcases%7D)
From the last equation, you have
![a=1](https://tex.z-dn.net/?f=a%3D1)
. Plug this into the second equation to get
![4+b=3\implies b=-1](https://tex.z-dn.net/?f=4%2Bb%3D3%5Cimplies%20b%3D-1)
. Plug these into the first to get
![4-2+c=5\implies c=3](https://tex.z-dn.net/?f=4-2%2Bc%3D5%5Cimplies%20c%3D3)
.
So the polynomial is
Answer:
option c is the right answer
Answer:
0
Step-by-step explanation:
Draw a Punnett square:
![\left[\begin{array}{ccc}&E&E\\e&Ee&Ee\\e&Ee&Ee\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%26E%26E%5C%5Ce%26Ee%26Ee%5C%5Ce%26Ee%26Ee%5Cend%7Barray%7D%5Cright%5D)
There's only one possible genotype the offspring can have: Ee. Since E is dominant, the offspring will have black eyes. So the probability of one of the offspring having red eyes is 0.
Answer:
B! Can I plz have Brainliest!!!!
Step-by-step explanation:
I've never gotten one before!