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Answer:
The above code print the text at three times.
Explanation:
- It is because the above code has one loop which executes three times. The loop executes for the value of i = 0,1 and 10.
- when the value of i is 0 then "++i" will increase the value 1 and the text will be printed.
- If the value of i=1, then the value of i is 2 in the second iteration and the again the text is printed, then the if condition gives the true result and the value of i will be 10.
- Then the loop executes for the last time when the value of i is 10.Then the value will be 11 because of the increment operator and the text will be printed for the third time.
- Then the while loop is not true for the 11 value of i and the loop will get terminated.
Windows server 2008 R2 and windows vista
Im would say c
hope i helped
Answer:
#include<iostream>
#include<cstring>
#include <algorithm>
using namespace std;
class Student{
public:
string name;
int rollNo;
Student(){
}
Student(string n, int r){
name = n;
rollNo = r;
}
};
class ClassRoom{
public:
Student stud[10];
int count;
ClassRoom(){
count = 0;
}
void addStudent(string str,int roll){
Student s(str,roll);
stud[count++] = s;
}
Student * getAllStudents(){
return stud;
}
};
int main()
{
string name;
char temp[20];
int rollNo, N, i;
Student * students;
ClassRoom classRoom;
i=0;
while(getline(cin, name) && cin.getline(temp,20)&&i<10){
rollNo = atoi(temp);
classRoom.addStudent(name, rollNo);
i++;
}
N = i;
students = classRoom.getAllStudents();
for(int i=0 ; i < N; i++){
cout << (students+i)->rollNo << " - " << (students+i)->name;
if(i<N-1)
cout<<endl;
}
return 0;
}
Explanation:
- In the addStudent method, increment the counter and as the value of variable s to the the stud array.
- In the getAllStudents method, return all the students.
- Finally in the main method, display the name and roll no. of students.
