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3 years ago

Write an equation of the line that passes through (2001, 35) and (2004.5, 16.1 ) points

Mathematics

1 answer:

Allisa [31]3 years ago

7 0

Answer: If you are looking for Slope-Intercept form (y=mx+b), It would be...

y=-5.4x+10840.4.

If you are looking for Point-Slope form, it would be...

y=-5.4x+10840.4.

Step-by-step explanation: Write in Slope-Intercept from, y=mx+b.

Point-Slope form : Use the Point-Slope formula, y-y1=m(x-x1) to find the equation of the line.

I hope this helps you out! ☺

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Explain or show how you could find by using the value of 5⋅3. If needed, use this diagram to support your reasoning.

Anika [276]

Answer:

Step-by-step explanation:

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3 years ago

Which best explains whether or not ABC = LMN?

Masja [62]

Answer:

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3 years ago

Evaluate the expression. 0.1×( – 0.9+ – 0.2÷ – 0.5) Write your answer as an integer or a decimal. Do not round.

matrenka [14]

Answer:

-0.05

Step-by-step explanation:

Given the expression :

0.1×( – 0.9+ – 0.2÷ – 0.5)

Evaluating the bracket :

0.1 * (-0.9 - 0.2 ÷ - 0.5)

Solving the division first

-0.2 ÷ - 0.5 = 0.4

Now we have ;

0.1 * (-0.9 + 0.4)

0.1 * - 0.5

= - 0.05

4 0

3 years ago

How to solve this question

VMariaS [17]

The variance method is as follows.

-Sum the squares of the values in data set, and then divide by the number of values in data set
- From that, subtract the square of the mean (add all values and divide by number of values in the data set)

Our variance is

 $\displaystyle\sigma^2 = \frac{2^2 + 5^2 + m^2}{3} - \left(\frac{2 + 5 + m}{3}\right)^2$

Since variance has to be 14, we set $\sigma^2 = 14$ and solve for m

$14= \frac{4 + 25 + m^2}{3} - \left(\frac{7 + m}{3}\right)^2\ \Rightarrow \\ \\
14 = \frac{29}{3} + \frac{1}{3}m^2 - \frac{1}{9}(7+m)^2 \\ \\
14 = \frac{29}{3}+ \frac{1}{3}m^2 - \frac{1}{9}(49 + 14m + m^2) \\ \\
14 = \frac{29}{3}+ \frac{1}{3}m^2 - \frac{49}{9}- \frac{14}{9}m- \frac{1}{9}m^2 \\ \\
0 = \frac{-88}{9} -\frac{14}{9}m + \frac{2}{9}m^2
$

quadratic formula

$m = \displaystyle\frac{-b \pm \sqrt{b^2 -4ac}}{2a} \\
m = \frac{-(-\frac{14}{9}) \pm \sqrt{\left(-\frac{14}{9}\right)^2 - 4(2/9)(-88/9)} }{2(2/9)} \\
m = \frac{\frac{14}{9} \pm \sqrt{ \frac{196}{81} + \frac{704}{81} } }{\frac{4}{9} } \\
m = \frac{\frac{14}{9} \pm \sqrt{ \frac{900}{81} } }{\frac{4}{9} } \\
m = \frac{\frac{14}{9} \pm \sqrt{ \frac{100}{9} } }{\frac{4}{9} } \\
m = \frac{\frac{14}{9} \pm \frac{10}{3} }{\frac{4}{9} } \\
m = 11, -4$

-4 doesnt' work as it is not a positive integer

m = 11

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3 years ago

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Mice21 [21]

Answer:

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3 years ago