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3 years ago

What are these rounded to the nearest tenth help 1)1017.36 2)1139.82

Mathematics

2 answers:

ziro4ka [17]3 years ago

8 0

Answer:

1. 1017.4

2. 1139.8

Step-by-step explanation:

Those the answers

Mazyrski [523]3 years ago

7 0

Answer: 1,017.4 and 1,139.8

Step-by-step explanation:

If the digit after tenth is greater than or equal to 5, add 1 to tenth. Else remove the digit.

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Aurora is planning to participate in an event at her school's field day that requires her to complete tasks at various stations

labwork [276]

Step-by-step explanation:

A. this is a geometric sequence.

according to y-coordinates =>

3, 6, 12, 24

have a T1 = 3 and ratio = 6/3 = 2

B. the formula = Tn = r. T(n-1)

T5 = 2. T4

= 2. 24 = 48 minutes

C. the formula : Tn = T1 . r^(n-1)

T9 = 3. 2^(9-1)

= 3. 2^8

= 3. 256

= 768 munutes

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2 years ago

In the year 2008, a company made $8.6 million in profit. For each consecutive year after that, their profit increased by 10%. Ho

goldenfox [79]

Answer:

12,040,000

Step-by-step explanation:

You would first do 8.6 million times 0.10 and then you would multiply that times 4 bc of 4 years that passed and finally add to 8.6 million!

5 0

3 years ago

What is the slope of the line shown? Answers A: 3 B:2 C:1/2 D:-3

satela [25.4K]

Answer:

-3

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

A tank initially contains 60 gallons of brine, with 30 pounds of salt in solution. Pure water runs into the tank at 3 gallons pe

adoni [48]

Answer:

the amount of time until 23 pounds of salt remain in the tank is 0.088 minutes.

Step-by-step explanation:

The variation of the concentration of salt can be expressed as:

$\frac{dC}{dt}=Ci*Qi-Co*Qo$

being

C1: the concentration of salt in the inflow

Qi: the flow entering the tank

C2: the concentration leaving the tank (the same concentration that is in every part of the tank at that moment)

Qo: the flow going out of the tank.

With no salt in the inflow (C1=0), the equation can be reduced to

$\frac{dC}{dt}=-Co*Qo$

Rearranging the equation, it becomes

$\frac{dC}{C}=-Qo*dt$

Integrating both sides

$\int\frac{dC}{C}=\int-Qo*dt\\ln(\abs{C})+x1=-Qo*t+x2\\ln(\abs{C})=-Qo*t+x\\C=exp^{-Qo*t+x}$

It is known that the concentration at t=0 is 30 pounds in 60 gallons, so C(0) is 0.5 pounds/gallon.

$C(0)=exp^{-Qo*0+x}=0.5\\exp^{x} =0.5\\x=ln(0.5)=-0.693\\$

The final equation for the concentration of salt at any given time is

$C=exp^{-3*t-0.693}$

To answer how long it will be until there are 23 pounds of salt in the tank, we can use the last equation:

$C=exp^{-3*t-0.693}\\(23/60)=exp^{-3*t-0.693}\\ln(23/60)=-3*t-0.693\\t=-\frac{ln(23/60)+0.693}{3}=-\frac{-0.959+0.693}{3}= -\frac{-0.266}{3}=0.088$

5 0

3 years ago

Last week the cost of a pair of socks was $3.25. This week they are on sale for $1.95. What is the percent change from last week

Alex_Xolod [135]

Answer:

The socks are 40% off, and it is decreased to 60%.

Step-by-step explanation:

:))

8 0

2 years ago