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Murrr4er [49]
3 years ago
7

I'm trying to find the standard form for 8.97x10 to rh negative 1. Can you helpe?

Mathematics
1 answer:
jeka943 years ago
7 0
<span><span><span>10000 = 1 x 104</span><span>24327 = 2.4327 x 104</span></span> <span><span>1000 = 1 x 103</span><span>7354 = 7.354 x 103</span></span> <span><span>100 = 1 x 102</span><span>482 = 4.82 x 102</span></span> <span><span>10 = 1 x 101</span><span>89 = 8.9 x 101 (not usually done)</span></span> <span><span>1 = 100</span>
</span> <span><span>1/10 = 0.1 = 1 x 10<span>-1</span></span><span>0.32 = 3.2 x 10<span>-1</span> (not usually done)</span></span> <span><span>1/100 = 0.01 = 1 x 10<span>-2</span></span><span>0.053 = 5.3 x 10<span>-2</span></span></span> <span><span>1/1000 = 0.001 = 1 x 10<span>-3</span></span><span>0.0078 = 7.8 x 10<span>-3</span></span></span> <span><span>1/10000 = 0.0001 = 1 x 10<span>-4</span></span><span>0.00044 = 4.4 x 10<span>-4</span></span></span></span> . Look at this.
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3 years ago
The diameter of a particle of contamination (in micrometers) is modeled with the probability density function f(x)= 2/x^3 for x
RoseWind [281]

Answer:

a) 0.96

b) 0.016

c) 0.018

d) 0.982

e) x = 2

Step-by-step explanation:

We are given with the Probability density function f(x)= 2/x^3 where x > 1.

<em>Firstly we will calculate the general probability that of P(a < X < b) </em>

       P(a < X < b) =  \int_{a}^{b} \frac{2}{x^{3}} dx = 2\int_{a}^{b} x^{-3} dx

                            = 2[ \frac{x^{-3+1} }{-3+1}]^{b}_a   dx    { Because \int_{a}^{b} x^{n} dx = [ \frac{x^{n+1} }{n+1}]^{b}_a }

                            = 2[ \frac{x^{-2} }{-2}]^{b}_a = \frac{2}{-2} [ x^{-2} ]^{b}_a

                            = -1 [ b^{-2} - a^{-2}  ] = \frac{1}{a^{2} } - \frac{1}{b^{2} }

a) Now P(X < 5) = P(1 < X < 5)  {because x > 1 }

     Comparing with general probability we get,

     P(1 < X < 5) = \frac{1}{1^{2} } - \frac{1}{5^{2} } = 1 - \frac{1}{25} = 0.96 .

b) P(X > 8) = P(8 < X < ∞) = 1/8^{2} - 1/∞ = 1/64 - 0 = 0.016

c) P(6 < X < 10) = \frac{1}{6^{2} } - \frac{1}{10^{2} } = \frac{1}{36} - \frac{1}{100 } = 0.018 .

d) P(x < 6 or X > 10) = P(1 < X < 6) + P(10 < X < ∞)

                                = (\frac{1}{1^{2} } - \frac{1}{6^{2} }) + (1/10^{2} - 1/∞) = 1 - 1/36 + 1/100 + 0 = 0.982

e) We have to find x such that P(X < x) = 0.75 ;

               ⇒  P(1 < X < x) = 0.75

               ⇒  \frac{1}{1^{2} } - \frac{1}{x^{2} } = 0.75

               ⇒  \frac{1} {x^{2} } = 1 - 0.75 = 0.25

               ⇒  x^{2} = \frac{1}{0.25}   ⇒ x^{2} = 4 ⇒ x = 2  

Therefore, value of x such that P(X < x) = 0.75 is 2.

8 0
3 years ago
I need helpppp:( like im failing this class
Olin [163]

Answer:

dont even stress i gotchu

It's 50*, 46* and 84*.

Ratio of the second problem is 1:1 they both have a slope of 1 (which is probably why all three points are on the same line)

Step-by-step explanation:

Since we know that the straight/flat angle would equal 180* we will set the total of all those angles to 180*

We will add them up to find x. Once we find x we can find the value of each angle.

6x-10 + 4x + 6 + 7x  + 14 = 180

We will combine like terms and solve for x.

17x+10 = 180

17x = 170

x = 10.

Since we have x = 10, we will plug it into x of each angle to get the value of each angle.

6(10) -10 = 60-10 which equals 50*

4(10) + 6 = 40+6 which equals 46*

7(10) + 14 = 70 + 14 which equals 84*.

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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