Answer:
a. 0.01
b. 0.001
c. The identification field of the packet fragment can be used to uniquely identify and collate the fragments lost in transmission.
Explanation:
The probability of losing a packet is 10% or 0.1, so the probability of losing the packet twice during transmission;
= 0.1 x 0.1 = 0.01
When any fragments have been part of the transmission, the probability of the packet is dependent on the fragments;
= 0.01 x 0.1 = 0.001
The identification field is a unique 16-bit value assigned to an IPv4 packet, when a packet is fragmented for transmission, its field is used to collate the unique fragments in the packet.
Different video files and operating system versions can cause compatibility issues to arise between computer systems.
Since, file formats and operating systems may not be compatible with each other. For example, earlier versions of Windows may not be able to play certain types of video files due to the codecs used to encode them.
<h3>Importance of compatibility between operating system computer systems</h3>
Compatibility between operating systems is important because it allows different computer systems to interact and share resources. This includes sharing of programs, files, and data.
Compatibility also allows users to access applications and services on different platforms. It also enables efficient use of hardware and software resources, as well as efficient use of resources in a network. Compatibility also ensures that computer systems can communicate with each other and can access the same resources. Without compatibility, it would be difficult for computer systems to interact with each other.
What are two compatibility issues that may arise between computer systems while transferring presentations? (Fill in the blank).
Different video files and _____ can cause compatibility issues to arise between computer systems.
Learn more about Compatibility between operating systems:
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Answer:
showProduct(int,double)
for example: showProduct(10,10.5) is the correct answer even showProduct(10,10.0) is also correct but showProduct(10.0,10.5) or showProduct(10,10) or showProduct(10.0,10) are wrong calls.
Explanation:
The code is
- <em>public static void showProduct (int num1, double num2){</em>
- <em> int product;</em>
- <em> product = num1*(int)num2;</em>
- <em> System.out.println("The product is "+product);</em>
- <em> }</em>
showProduct is function which asks for two arguments whenever it is called, first one is integer and second one is of type double which is nothing but decimal point numbers. Generally, in programming languages, 10 is treated as integer but 10.0 is treated as decimal point number, but in real life they are same.
If showProduct( 10,10.0) is called the output will be 'The product is 100'.
Strange fact is that, if you enter showProduct(10,10.5) the output will remain same as 'The product is 100'. This happens because in the 3rd line of code,which is <em>product=num1*(int)num2</em>, (int) is placed before num2 which makes num2 as of type integer, which means whatever the value of num2 two is given, numbers after decimal is erased and only the integer part is used there.
This is necessary in JAVA and many other programming languages as you <u>cannot</u><u> multiply two different datatypes</u> (here one is int and another is double). Either both of them should be of type int or both should be of type double.
