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3 years ago

15

Clark made four of his truck payments late and was fined four late fees. The total change to his savings from late fees was -$40

. How much was one late fee?

1 answer:

aniked [119]3 years ago

7 0

$10 for one late fee

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Please help! 10 points

Orlov [11]

<h2>Greetings!</h2>

Answer:

Angle A is 118°

Step-by-step explanation:

All angles in a circle add up to 180, so this means that all the measurements of the three angles add to 180:

x + 2x + 13 + x - 8 = 180

Clean it up:

3x + x + x + 13 -8

5x -5 = 180

To isolate the 5x, you need to move the +5 over to the other side, making it a negative 5:

5x = 180 - 5

5x = 175

Now divide each side by 5 to get the value of 1x:

$\frac{5x}{5} = \frac{175}{5}$

x = 35

So angle A is:

3x + 13

3(35) + 13 = 118

<h3>So angle A is 118°</h3>
<h2>Hope this helps!</h2>

8 0

3 years ago

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Luda [366]

Answer:

Y=⅘X+2. the picture not clear so i hesitate

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2 years ago

Helpppppppppppppppppppppppppppppppppppppppppppp

Elan Coil [88]

Answer:

The slope is m=2

Step-by-step explanation:

7 - 3 = 4 in y

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3 years ago

In a recent year, Washington State public school students taking a mathematics assessment test had a mean score of 276.1 and a s

Oksi-84 [34.3K]

Answer:

a) $\mu_{\bar x} =\mu = 276.1$

$\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3$

b) From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)$

c) $P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)$

$P(Z\geq2.070)=1-P(Z$

Step-by-step explanation:

Let X the random variable the represent the scores for the test analyzed. We know that:

$\mu=E(X) = 276.1 , \sigma=Sd(X) = 34.4$

And we select a sample size of 64.

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Part a

For this case the mean and standard error for the sample mean would be given by:

$\mu_{\bar x} =\mu = 276.1$

$\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3$

Part b

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)$

Part c

For this case we want this probability:

$P(\bar X \geq 285)$

And we can use the z score defined as:

$z=\frac{\bar x -\mu}{\sigma_{\bar x}}$

And using this we got:

$P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)$

And using a calculator, excel or the normal standard table we have that:

$P(Z\geq2.070)=1-P(Z$

8 0

3 years ago

I have a math question it is... what is g - 3/7 = 2/7 ?

stira [4]

g - 3/7 = 2/7 is an equation.

$\displaystyle\bf\\g-\frac{3}{7}=\frac{2}{7}\\ \\g=\frac{2}{7}+\frac{3}{7}=\frac{2+3}{7}=\frac{5}{7}\\\\\boxed{\bf g=\frac{5}{7}}$

6 0

2 years ago