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irga5000 [103]
3 years ago
7

When choosing an item from a group, researchers have shown that an important factor influencing choice is the item's location. T

his occurs in varied situations such as shelf positions when shopping, filling out a questionnaire, and even choosing a preferred candidate during a presidential debateIn this experiment, five identical pairs of white socks were displayed by attaching them vertically to a blue background that was then mounted on an easel for viewingOne hundred participants from the University of Chester were used as subjects and asked to choose their preferred pairs of socksIn situations of this type, subjects often exhibit the "center stage effect," which is a tendency to choose the item in the center. this experiment, 34 subjects chose the pair of socks in the center. Are these data evidence of the "center stage effect"? STATE: Are the students choosing pairs of socks randomly? If the students were choosing socks at random, what would be the chance, of a pair being selected? (Enter your answer rounded to one decimal place.) p 0
Mathematics
1 answer:
natka813 [3]3 years ago
7 0

Answer:

a) We have evidence of the " center stage effect" pair number 3 was selected 34 times almost double the probability of random process

b) probability of ocurrency in random case is 20 %

Step-by-step explanation:

To answer this question we first look at the probability of chossing a pair in case of random selection

P = successful event / total outcomes

P₁ = 1/5

P₁ = 0,2    or   P₁ = 20 %

Then if the central pair was selected  34 times from 100 participants          ( almost the double ) we have evidence of the center stage effect

P₂  = 34/100   or   P₂  = 0,34

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A jar contains n nickels and d dimes. There is a total of 253 coins in the jar. The value of the coins is $15.95. How many nicke
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There are 187 nickels and 66 dimes in the jar.

Step-by-step explanation:

Given,

Total coins = 253

Value of coins = $15.95 = 15.95*100 = 1595 cents

Value of each nickel = 5 cents

Value of each dime = 10 cents

According to given statement;

x+y=253     Eqn 1

5x+10y=1595     Eqn 2

Multiplying Eqn 1 by 5

5(x+y=253)\\5x+5y=1265\ \ \ Eqn\ 3

Subtracting Eqn 3 from Eqn 2

(5x+10y)-(5x+5y)=1595-1265\\5x+10y-5x-5y=330\\5y=330

Dividing both sides by 5

\frac{5y}{5}=\frac{330}{5}\\y=66

Putting y=66 in Eqn 1

x+66=253\\x=253-66\\x=187

There are 187 nickels and 66 dimes in the jar.

Keywords: linear equation, elimination method

Learn more about elimination method at:

  • brainly.com/question/12905000
  • brainly.com/question/12918501

#LearnwithBrainly

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