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2 years ago

Can someone help me with factoring by grouping x^3 + x^2 - 25x - 25 please show work

1 answer:

7 0

(x+1)(x+5)(x−5)...is the answer
Factor x3+x2−25x−25x3+x2−25x−25=(x+1)(x+5)(x−5)

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In a certain urban are, the relationship between , number of students ,x, in thousands, and the number schools, y, has an x-inte

chubhunter [2.5K]

Answer:

-12 = 3x - 4y

Step-by-step explanation:

Two points on the graph are (-4, 0) and (0, 3). Moving from the first point to the second, we see x (the 'run') increase by 4 and y (the 'rise') increase by 3. Thus, the slope of this line is m = rise / run = 3/4.

Using the point slope form, we get:

y - 3 = (3/4)(x - 0), or

4y - 12 = 3x, or

-12 = 3x - 4y (which is in Standard Form).

6 0

2 years ago

Please help on this?

Yakvenalex [24]

A. is right

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8 0

3 years ago

Read 2 more answers

Choose the appropriate pattern and use it to find the product: (p4−q4)(p4+q4).

sp2606 [1]

The expression can be solved by expanding the bracket and multiplying out the terms

$(p^4-q^4)(p^4+q^4)$ $\begin{gathered} =p^4(p^4+q^4)-q^4(p^4+q^4) \\ =p^8+p^4q^4-p^4q^4-q^8 \\ =p^8-q^8 \end{gathered}$

Therefore, the expression can be simplified as;

$p^8-q^8$

Alternatively, using the theorem of difference of two squares, which is

$a^2-b^2=(a-b)(a+b)$

Hence,

$p^8-q^8=(p^4)^2-(q^4)^2$

7 0

1 year ago

The perimeter of a triangle is 37. One side of triangle is one foot longer than the second side. The third side is tgree feet lo

disa [49]

Answer:

First: 12 feet

Second: 11 feet

Third: 14 feet

Step-by-step explanation:

Let the second side of the traingle be x

First side of the triangle= x+1

Third side of the triangle= x+3

x+x+1+x+3 = 37

3x+4 = 37

3x = 37-4

3x = 33

x = 11

First side of the triangle= (11)+1

= 12

Second side of the triangle= 11

Third side of the triangle= (11)+3

= 14

5 0

3 years ago

A right triangle has an area of 18 The length of each leg is 6 inches. If the triangle is not an isosceles triangle, what are al

ladessa [460]

Given:

Area of a right triangle = 18 sq. inches

Length of one leg = 6 inches

To find:

The length of another leg.

Solution:

We know that, the area of a triangle is

$A=\dfrac{1}{2}\times base\times height$

In a right angle triangle, the area of the triangle is

$A=\dfrac{1}{2}\times leg_1\times leg_2$

Putting A=18 and $leg_1=6$ , we get

$18=\dfrac{1}{2}\times 6\times leg_2$

$18=3\times leg_2$

Divide both sides by 3.

$\dfrac{18}{3}=leg_2$

$6=leg_2$

Both legs are equal so the given triangle is an isosceles right triangle.

If the triangle is not isosceles triangle, then the length of legs are factors of 36 because half of 36 is 18.

Therefore, the possible pairs of legs are 1 and 36, 2 and 18, 3 and 12, 4 and 9, 6 and 6, 9 and 4, 12 and 3, 18 and 2, 36 and 1.

5 0

3 years ago