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krok68 [10]
3 years ago
10

Find the value of X to the nearest tenth (giving brainliest and thanks to all!)

Mathematics
2 answers:
Nina [5.8K]3 years ago
5 0

Answer:

C

Step-by-step explanation:

deff fn [24]3 years ago
3 0
The answer to this question is 12.96 but you round up to 13 so its c
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868 ÷ 14 = ?? i need help lol
sasho [114]

Answer:

**********************868/14=62********************

Step-by-step explanation:

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Which statement is true about the value of |6|?​
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What are the options?
6 0
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Information for the park trails is displayed at the entrance to the park office.
Lisa [10]
So you can use tan here, which is opposite/adjacent. (We're looking for the Adjacent)

Since we know Trail E is 1700, we're looking for the patch of trail A that is the adjacent. So if we put 42 into a tan calculator we get about 0.9.

So that means that 1,700 / adjacent = 0.9.

So we can also say

1,700/0.9 = adjacent

or, 1,700/0.9 = 1888.89

Now, we have the little patch of trail A in the smaller right triangle. We want to find the patch of trail A in the larger right triangle.

So just do 5,000 - 1,888.89

You get 3111.11

So if we know that's that, and we're looking for the hypotenuse, or Trail B, we can use cosine, because that's adjacent / hypotenuse.

So 42 in a cosine calculator is 0.74 ish.

So 3111.11 / hypotenuse = 0.74

Or 3111.11 / 0.74 = hypotenuse

Or 3111.11 / 0.74 = 4204

So Trail C should be 4204 feet long.
7 0
3 years ago
What is 3/8 as a precent
Contact [7]

The answer to this question is 37.5%

7 0
3 years ago
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Please help?!
Anton [14]

Answer:

Δ PQT ~ Δ QRS  .....{S-S-S test for similarity}...Proof is below.

Step-by-step explanation:

Given:

In Δ PQT

PQ = 30 ft

QT = 28 ft

TP = 20 ft

In Δ QRS

QR = 15 ft

RS = 14 ft

SQ = 10 ft

To Prove:

Δ PQT ~ Δ QRS

Proof:

First we consider  the ratio of the sides

\frac{PQ}{QR}=\frac{30}{15} = \frac{2}{1}            ..............( 1 )

\frac{QT}{RS}=\frac{28}{14} = \frac{2}{1}            ..............( 2 )

\frac{TP}{SQ}=\frac{20}{10} = \frac{2}{1}            ..............( 3 )

So By equation ( 1 ), ( 2 ) and  ( 3 ) we get

\frac{PQ}{QR}=\frac{QT}{RS} = \frac{TP}{SQ}

Now in Δ PQT  and Δ QRS we have

\frac{PQ}{QR}=\frac{QT}{RS} = \frac{TP}{SQ}

Which are corresponding sides of a similar triangle in proportion.

∴ Δ PQT ~ Δ QRS  .....{S-S-S test for similarity}...Proved

8 0
3 years ago
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