Question

Expand the brackets

Answer 1

$1)\ 3(2x + 5) = 6x + 15\\\\2)\ 7(p + 3q) = 7p + 21q\\\\3)\ 3m(n - 2m) = 3mn - 6m^2$

Solution:

Given that,

We have to expand the brackets

Use distributive property,

a(b + c) = ab + bc

Multiply the number in front of parenthesis with each term inside the parenthesis and then add them together

1)

$3(2x + 5) = 3 \times 2x + 3 \times 5\\\\3(2x + 5) = 6x+15$

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2)

$7(p + 3q) = 7 \times p + 7 \times 3q\\\\7(p + 3q) =7p + 21q$

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3)

$3m(n-2m) = 3m \times n - 3m \times 2m\\\\3m(n-2m) = 3mn - 6m^2$

Thus the given expressions are expanded using distributive property