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joja [24]
3 years ago
12

Please solve this The real one don't solve till you see the equation

Mathematics
1 answer:
Afina-wow [57]3 years ago
7 0
The answer is 40 good luck
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Ralph has a piece of shelving 3 m long. He is going to cut it into 4 equal lengths pieces. how long will each piece be?
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0.75 or 3/4 m each.

Extra letters: cdvaysoHAHboaihscvia


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6x-5y&gt;35 <br> On a graph
Colt1911 [192]

Answer:

See attached photo

Step-by-step explanation:

6x-5y>35

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PLZ help will give brainliest and 60 points asap
vovangra [49]

Answer:

A. -2 + 12 -2 ^ 3 + 2 ^ 0 * 3

= 10 - 2 ^ 3 + 2 ^ 0 * 3

= 10 - 8 + 1

= 3

B. 9 ^ (1/2)(25) - 8 + 2 + 3 ^ 2

= 9 ^ (1/2)(25) - 6 + 9

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= 847288609446

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Write the linearization of the function at the points indicated. (Enter your answer as an equation. Let x be the independent var
Natalija [7]

Answer:

\displaystyle y=5+\frac{x}{10}

\displaystyle y=10+\frac{(x-75)}{20}

Step-by-step explanation:

<u>Linearization</u>

It consists of finding an approximately linear function that behaves as close as possible to the original function near a specific point.

Let y=f(x) a real function and (a,f(a)) the point near which we want to find a linear approximation of f. If f'(x) exists in x=a, then the equation for the linearization of f is

y=f(x)=f(a)+f'(a)(x-a)

Let's find the linearization for the function

y=\sqrt{25+x}

at (0,5) and (75,10)

Computing f'(x)

\displaystyle f'(x)=\frac{1}{2\sqrt{25+x}}

At x=0:

\displaystyle f'(0)=\frac{1}{2\sqrt{25+0}}=\frac{1}{10}

We find f(0)

f(0)=\sqrt{25+0}=5

Thus the linearization is

\displaystyle y=f(0)+f'(0)(x-0)=5+\frac{1}{10}x

\displaystyle y=5+\frac{x}{10}

Now at x=75:

\displaystyle f'(75)=\frac{1}{2\sqrt{25+75}}=\frac{1}{20}

We find f(75)

f(75)=\sqrt{25+75}=10

Thus the linearization is

\displaystyle y=f(75)+f'(75)(x-75)=10+\frac{1}{20}(x-75)

\displaystyle y=10+\frac{(x-75)}{20}

5 0
3 years ago
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