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Serggg [28]
3 years ago
11

Amber and Linda are 54 miles apart, traveling towards each other. If Linda travels 11 mph and Amber travels 7 mph how long(hours

) until they meet?
Mathematics
1 answer:
USPshnik [31]3 years ago
7 0
Bro I am in 5 th grade and ik this....
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Use the present value formula to determine the amount to be invested​ now, or the present value needed.
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Answer:

Present value is $29,086.21.

Step-by-step explanation:

PV =\frac{40000}{(1+\frac{0.029}{12} )^{11*12} }=29,086.21

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Estimate the closest to the actual value of (2.9983) · (1.8792)<br> to the nearest tenths place.
Fantom [35]

Answer:

3 & 2

Explanation:

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A=1+Prt solve for p
lilavasa [31]

A=1+Prt\\\\Prt=A-1\\\\P=\dfrac{A-1}{rt}

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4 years ago
Eighteen telephones have just been received at an authorized service center. Six of these telephones are cellular, six are cordl
LenaWriter [7]

Answer:

a) 0.0498

b) 0.1489

c) 0.1818

Step-by-step explanation:

Given:

Number of telephones = 6+6+6= 18

6 cellular, 6 cordless, and 6 corded.

a) Probability that all the cordless phones are among the first twelve to be serviced:

12 are selected from 18 telephones, possible number of ways of selection = ¹⁸C₁₂

Then 6 cordless telephones are serviced, the remaining telephones are: 12 - 6 = 6.

The possible ways of selecting thr remaining 6 telephones = ¹²C₆

Probability of servicing all cordless phones among the first twelve:

= (⁶C₆) (⁶C₁₂) / (¹⁸C₁₂)

= \frac{1 * 924}{18564}

= 0.0498

b) Probability that after servicing twelve of these phones, phones of only two of the three types remain to be serviced:

Here,

One type must be serviced first

The 6 remaining to be serviced can be a combination of the remaining two types.

Since there a 3 ways to select one type to be serviced, the probability will be:

= 3 [(⁶C₁)(⁶C₅) + (⁶C₂)(⁶C₄) + (⁶C₃)(⁶C₃) + (⁶C₄)(⁶C₂) + (⁶C₅)(⁶C₁)] / ¹⁸C₁₂

= \frac{3 * [(6)(6) + (15)(15) + (20)(20) + (15)(15) + (6)(6)]}{18564}

= \frac{2766}{18564}

= 0.1489

c) probability that two phones of each type are among the first six:

(⁶C₂)³/¹⁸C₆

\frac{3375}{18564}

=0.1818

5 0
4 years ago
Simplify the following in the form of a + b √c<br><br>2√2-7√8+4√½+8√32​
Kryger [21]

Answer:

undefined

Step-by-step explanation:

the square root of a negative number doesnt exist in the set of Real numbers

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