Answer:
x intercepts -sqrt(5), + sqrt(5)
y intercept -5
Step-by-step explanation:
y = x^2 -5
to find the x intercept set y=0 and solve for x
0 = x^2-5
add 5 to each side
5 = x^2
take the square root of each side
+- sqrt(5) = sqrt(x^2)
x = +-sqrt(5) there are 2 x intercepts since it is a quadratic
to find the y intercept set x=0 and solve for y
y = 0-5
y = -5
The equation 
in standard form looks like 
.
Given equation of sphere be .
We are required to express the given equation in the standard form of the equation of sphere.
Equation is basically relationship between two or more variables that are expressed in equal to form. Equation of two variables look like ax+by=c. It may be linear equation,quadratic equation, cubic equation or many more depending on the powers of variables. The standard form of the equation of sphere looks like 
.
The given equation is .
We have to break 22 which is in right side into various parts according to the left side of the equation.
Hence the equation in standard form looks like .
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Yes your answer would be correct! :)
Answer:
Part A: impossible
Part B: Either equal or blue
Part C: 9 green and 2 blue were added
Step-by-step explanation:
Part A:
The only colors included in this problem are red, blue, and green. There is no black colored pencil, therefore, it is impossible to get one from the box.
Part B:
I'm not sure what you're asking in this question, but I will give you the two choices. If it is before the additional 11 colored pencils are added to the box, the chance of drawing a red and the chance of drawing a blue will be equal, because both of them have 11 of each color. If it is after the additional 11 colored pencils are added to the box, then the chance of drawing a blue colored pencil will be greater than the chance of drawing a red colored pencil. After the 11 colored pencils are added, there are 13 blue and 11 red. The blue is greater.
Part C:
The least number of green colored pencils added has to be 9, because the chance of drawing a green pencil is now greater than the chance of drawing a red pencil. If we add 8 more green pencils, the likelihood would be the same. Therefore, the number of green colored pencils added has to be at least 9. If we have the last 2 colored pencils be blue, then there would be 11 red, 13 blue, and 12 green. This fits all the conditions, therefore, adding 9 green colored pencils and 2 blue colored pencils is the answer.
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