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aivan3 [116]
4 years ago
9

-2b^2-5b+12 factor the trinomial

Mathematics
1 answer:
Bad White [126]4 years ago
5 0

Answer: −(b+4)(2b−3)

Step-by-step explanation:

1. Factor out the negative sign.

−(2b^2+5b−12)

2. Split the second term in 2b^2+5b−12 into two terms.

−(2b^2+8b−3b−12)

3.Factor out common terms in the first two terms, then in the last two terms.

−(2b(b+4)−3(b+4))

4. Factor out the common term b+4b+4b+4.

−(b+4)(2b−3)

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3 years ago
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laila [671]
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4 years ago
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lilavasa [31]

Those two functions just miss each other so there are no real solutions.  Every polynomial with complex coefficients has complex solutions.

2x^2 + 2 = 3x

2x^2 - 3x = -2

2( x^2 - \frac 3 2 x) = -2

x^2 - \frac 3 2 x = -1

x^2- \frac 3 2 x+ (\frac 3 4)^2= -1 + (\frac 3 4 )^2

(x - \frac 3 4)^2 = -\frac 7{16}

x - \frac 3 4 = \pm \sqrt{ -\frac 7{16}}

x = \frac 3 4 \pm \frac i 4 \sqrt{7}

x = \frac 1 4(3 \pm i \sqrt{7})


4 0
3 years ago
6xb is less than 12 but greater than 6
photoshop1234 [79]
I interpret your "xb" to mean "6 times b."  Please do not use " x " to indicate multiplication.  Use " * " if you wish.

6 < 6b < 12, which can be reduced to 1 < b < 2
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