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3 years ago

I don't know how to solve this. How would I solve this? Thanks!!!!

Mathematics

1 answer:

Afina-wow [57]3 years ago

6 0

Answer:

x = 11 units

Step-by-step explanation:

Area of triangle = (base + base 2) * h *1/2

so (7 + x )* 7 * 1/2 = 63

63 x 2 = 126

126 / 7 = 18

18-7 = x

x = 11

Check

(7+11)* 7 * 1/2

18* 7 = 126

126 x 0.5 = 63

CORRECT!

(p.s., tell me if wrong :P)

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Which statements are true about the components of a circle? Check all that apply.

Black_prince [1.1K]

Answer:

The radius is half the length of the diameter.

The circumference is the perimeter of a circle.

To find the circumference, multiply Pi by the diameter.

Step-by-step explanation:

3 0

3 years ago

the large Square above has area 9 is divided into 9 smaller squares of equal area what is the length of how strong and bold

Kay [80]

If one square is divided into 9 smaller equal squares, then they have to be arranged in 3 lines of 3, that is 3 smaller equal squares per side of the original big square. That said, the area of the big square is equal to the multiplication of 3 small squares sides times 3 small squares sides, call x the length of the small squares.
So,
area = 9 = 3x*3x
9x^2 = 9
x^2 = 1
x = 1
therefore the smaller squares have sides of 1 unit

8 0

3 years ago

PLEASE HELP I POSTED LIKE 2 HOURS AGO WITH THIS QUESTION AND I NEED HELP:)

garik1379 [7]

A system is inconsistent when there are no solutions between the two equations. Graphically, the lines will be parallel (they never meet!) and the slopes will be the same. But the y-intercepts will be different.

Let's look at the four equations, with each solved as needed, into y = mx + b form.

A: 2x + y = 5

y = 5 - 2x

y = -2x + 5

Compared to y = 2x + 5, the slopes are different, so this system won't be inconsistent. Not a good choice.

B: y = 2x + 5

Compared to y = 2x + 5, the slopes are the same and the y intercepts are the same. This system has infinitely many solutions. Not a good choice.

C: 2x - 4y = 10

-4y = 10 - 2x

-4y = -2x + 10

y = 2/4x -10/4

Here the slopes are different, so, like A this is not a good choice.

D: 2y - 4x = -10

2y = =10 + 4x

2y = 4x - 10

y = 2x - 5

Compared to y = 2x + 5 we have the same slopes and different y intercepts. The lines will be parallel and the system is inconsistent.

Thus, D is the best choice.

7 0

3 years ago

Read 2 more answers

A chemist is using 362 milliliters of a solution of acid and water. If 12.1% of the solution is acid, how many milliliters of ac

PSYCHO15rus [73]

Answer:

The answer to your question is 43.8 mL of acid.

Step-by-step explanation:

Data

Total volume = 362 ml

12.1 % is acid

The Volume of acid = ?

Process

1.- Use the rule of three and cross multiplication to solve this problem.

362 ml ------------------- 100%

x ------------------- 12.1 %

x = (12.1 x 362) / 100

x = 4380.2 / 100

x = 43.802 ml

2.- Round your answer to the nearest tenth.

43.802 only consider the first decimal

43.8 mL

3.- Conclusion

A 12.1% solution of acid has 43.8 mL of acid.

6 0

3 years ago

Read 2 more answers

Find the integral using substitution or a formula.

Nadusha1986 [10]

$\rm \int \dfrac{x^2+7}{x^2+2x+5}~dx$

Derivative of the denominator:
$\rm (x^2+2x+5)'=2x+2$

Hmm our numerator is 2x+7. Ok this let's us know that a simple u-substitution is NOT going to work. But let's apply some clever Algebra to the numerator splitting it up into two separate fractions. Split the +7 into +2 and +5.

$\rm \int \dfrac{x^2+2+5}{x^2+2x+5}~dx$

and then split the fraction,

$\rm \int \dfrac{x^2+2}{x^2+2x+5}~dx+\int\dfrac{5}{x^2+2x+5}~dx$

Based on our previous test, we know that a simple substitution will work for the first integral: $\rm \quad u=x^2+2x+5\qquad\to\qquad du=2x+2~dx$

So the first integral changes,

$\rm \int \dfrac{1}{u}~du+\int\dfrac{5}{x^2+2x+5}~dx$

integrating to a log,

$\rm ln|x^2+2x+5|+\int\dfrac{5}{x^2+2x+5}~dx$

Other one is a little tricky. We'll need to complete the square on the denominator. After that it will look very similar to our arctangent integral so perhaps we can just match it up to the identity.

$\rm x^2+2x+5=(x^2+2x+1)+4=(x+1)^2+2^2$

So we have this going on,

$\rm ln|x^2+2x+5|+\int\dfrac{5}{(x+1)^2+2^2}~dx$

Let's factor the 5 out of the intergral,
and the 4 from the denominator,

$\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\frac{(x+1)^2}{2^2}+1}~dx$

Bringing all that stuff together as a single square,

$\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\left(\dfrac{x+1}{2}\right)^2+1}~dx$

Making the substitution: $\rm \quad u=\dfrac{x+1}{2}\qquad\to\qquad 2du=dx$

giving us,

$\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\left(u\right)^2+1}~2du$

simplying a lil bit,

$\rm ln|x^2+2x+5|+\frac52\int\dfrac{1}{u^2+1}~du$

and hopefully from this point you recognize your arctangent integral,

$\rm ln|x^2+2x+5|+\frac52arctan(u)$

undo your substitution as a final step,
and include a constant of integration,

$\rm ln|x^2+2x+5|+\frac52arctan\left(\frac{x+1}{2}\right)+c$

Hope that helps!
Lemme know if any steps were too confusing.

8 0

3 years ago