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marissa [1.9K]
3 years ago
11

I don't know how to solve this. How would I solve this? Thanks!!!!

Mathematics
1 answer:
Afina-wow [57]3 years ago
6 0

Answer:

x = 11 units

Step-by-step explanation:

Area of triangle = (base + base 2) * h *1/2

so (7 + x )* 7 * 1/2 = 63

63 x 2 = 126

126 / 7 = 18

18-7 = x

x = 11

Check

(7+11)* 7 * 1/2

18* 7 = 126

126 x 0.5 = 63

CORRECT!

(p.s., tell me if wrong :P)

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libon's new car can travel 45 miles on 1 gallon of of gas. at this rate how far can the car travel on 7 gallons
Setler [38]

Answer:

315

Step-by-step explanation:

If one gallon of gas can give you 45 miles, than multiple 45 ( the miles ) times 7 (the gallons of gas) and you will have your answer :)

4 0
3 years ago
What is the value of the negative zero of the function, f, defined by<br> f(x) = x^2 - 16
Lelu [443]

Answer:

x = -4

Step-by-step explanation:

f(x) = x² - 16

This is the difference of squares

which factors as

f(x) = (x - 4)(x + 4)

Therefor the negative zero is

x = -4

8 0
3 years ago
If f(x) = x^2 + 1 and g(x) = 3x + 1, find [f(4)]^2 <br> 81 <br> 257 <br> 289
Vedmedyk [2.9K]
So g(x) doesn't come in
ok

remember pemdas
inside first
evaluate f(4)
f(4)=4^2+1=16+1=17
now we have

[17]^2=289

answer s 289
7 0
3 years ago
Read 2 more answers
Kind of lost, can anyone please help me find the answer and explain? Id really appreciate it.
stich3 [128]

Answer:

B. 45

Step-by-step explanation:

do 12×12 which is 144 then Davide it by 2 because it's a triangle then do 9×3 which is 27 then subtract that from 72 and you get 45.

5 0
3 years ago
Read 2 more answers
Y=-1/3x^2-4x-5 in vertex form
grigory [225]

Answer:

Y=-\frac{1}{3}(x+6)^2+7   [Vertex form]

Step-by-step explanation:

Given function:

Y=-\frac{1}{3}x^2-4x-5

We need to find the vertex form which is.,

y=a(x-h)^2+k

where (h,k) represents the co-ordinates of vertex.

We apply completing square method to do so.

We have  

Y=-\frac{1}{3}x^2-4x-5

First of all we make sure that the leading co-efficient is =1.

In order to make the leading co-efficient is =1, we multiply each term with -3.

-3\times Y=-3\times\frac{1}{3}x^2-(-3)\times4x-(-3)\times 5

-3Y=x^2+12x+15

Isolating x^2 and x terms on one side.

Subtracting both sides by 15.

-3Y-15=x^2+12x-15-15

-3Y-15=x^2+12x

In order to make the right side a perfect square trinomial, we will take half of the co-efficient of x term, square it and add it both sides side.  

square of half of the co-efficient of x term = (\frac{1}{2}\times 12)^2=(6)^2=36

Adding 36 to both sides.

-3Y-15+36=x^2+12x+36

-3Y+21=x^2+12x+36

Since x^2+12x+36 is a perfect square of (x+6), so, we can write as:

-3Y+21=(x+6)^2

Subtracting 21 to both sides:

-3Y+21-21=(x+6)^2-21

-3Y=(x+6)^2-21

Dividing both sides by -3.

\frac{-3Y}{-3}=\frac{(x+6)^2}{-3}-\frac{21}{-3}

Y=-\frac{1}{3}(x+6)^2+7   [Vertex form]

8 0
3 years ago
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