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3 years ago

How do you solve this equation? x/2 - x = x/4 + 6

Mathematics

1 answer:

fenix001 [56]3 years ago

4 0

Answer:

x= - 8

Step-by-step explanation:

multiply both sides by 4 to get rid of the fractions. you should then get:

2x-4x=x+24

then get all the x terms to one side by subtracting by x on each side:

2x-4x-x=24

then simplify:

-3x=24

divide by -3 on each side:

x= - 8

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Brady made a scale drawing of a rectangular swimming pool on a coordinate grid. The points (-20, 25), (30, 25), (30, -10) and (-

djverab [1.8K]

Answer:

Length = 50 units

width = 35 units

Step-by-step explanation:

Let A, B, C and D be the corner of the pools.

Given:

The points of the corners are.

$A(x_{1}, y_{1}})=(-20, 25)$

$B(x_{2}, y_{2}})=(30, 25)$

$C(x_{3}, y_{3}})=(30, -10)$

$D(x_{4}, y_{4}})=(-20, -10)$

We need to find the dimension of the pools.

Solution:

Using distance formula of the two points.

$d(A,B)=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ ----------(1)

For point AB

Substitute points A(30, 25) and B(30, 25) in above equation.

$AB=\sqrt{(30-(-20))^{2}+(25-25)^{2}}$

$AB=\sqrt{(30+20)^{2}}$

$AB=\sqrt{(50)^{2}$

AB = 50 units

Similarly for point BC

Substitute points B(-20, 25) and C(30, -10) in equation 1.

$d(B,C)=\sqrt{(x_{3}-x_{2})^{2}+(y_{3}-y_{2})^{2}}$

$BC=\sqrt{(30-30)^{2}+((-10)-25)^{2}}$

$BC=\sqrt{(-35)^{2}}$

BC = 35 units

Similarly for point DC

Substitute points D(-20, -10) and C(30, -10) in equation 1.

$d(D,C)=\sqrt{(x_{3}-x_{4})^{2}+(y_{3}-y_{4})^{2}}$

$DC=\sqrt{(30-(-20))^{2}+(-10-(-10))^{2}}$

$DC=\sqrt{(30+20)^{2}}$

$DC=\sqrt{(50)^{2}}$

DC = 50 units

Similarly for segment AD

Substitute points A(-20, 25) and D(-20, -10) in equation 1.

$d(A,D)=\sqrt{(x_{4}-x_{1})^{2}+(y_{4}-y_{1})^{2}}$

$AD=\sqrt{(-20-(-20))^{2}+(-10-25)^{2}}$

$AD=\sqrt{(-20+20)^{2}+(-35)^{2}}$

$AD=\sqrt{(-35)^{2}}$

AD = 35 units

Therefore, the dimension of the rectangular swimming pool are.

Length = 50 units

width = 35 units

7 0

3 years ago

One cell phone plan charges $20 per month plus $.15 per minute used. A second cell phone plan charges $35 per month plus $.10 pe

SOVA2 [1]

20+0.15x = 35+0.10x

0.15x=15+0.10x

0.05x=15

x= 15/0.05

x= 300minutes

check:

300*.015 = 45+20=65

300*0.10 = 30 + 35 = 65

they equal

so number of minutes would be 300

7 0

3 years ago

C + 1/4c<br> please help me i need this done now

abruzzese [7]

Answer:

$1\frac{1}{4} c$

Step-by-step explanation:

$c+\frac{1}{4}c$

Rewrite the expression

$= 1c+\frac{1}{4} c$

Add

$= 1\frac{1}{4} c$

Therefore, $c+\frac{1}{4}c$ is equal to $1\frac{1}{4} c$ .

I hope this helps!

5 0

3 years ago

Which of the following inequalities is correct?

almond37 [142]

Answer:

Step-by-step explanation:

because there variables represent 1 so 1 cant be bigger than one and the other two have real equations

6 0

2 years ago

The sum of two numbers is x If one of the numbers is 12, what is the other?

neonofarm [45]

X-12 will give the other number

6 0

3 years ago

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