Ask question

Ask question

All categories

2 years ago

6

a train car manufacturer has 828 Wheels each train and car needs for 16 wheels to carry heavy loads how many complete cars can t

he manufacturer make using 828 and wheels

1 answer:

Georgia [21]2 years ago

5 0

51.75 which is 52 because you tound up so it can carry approximately 52 cars because 828÷16=51.75 so it would be approximately 52

You might be interested in

Solve for x.<br><br> + 1 = 3<br><br> x = 1 <br> x = 2 <br> x = 3<br> x = 6

DENIUS [597]

X=2 because 3 minus 1 equals 2

3 0

3 years ago

Read 2 more answers

A pump fills a pool at a constant rate. At the end of 21 minutes it has filled 7 gallons of water. Which table represents the re

likoan [24]

Answer:

B.

Step-by-step explanation:

cuz you take 21 divide by 7 equals 3. 33 divided by 3 equals 11

i hope this is right!!! :)

6 0

2 years ago

Solve the inequality 2x>30+5/4x

insens350 [35]

Answer:

Step-by-step explanation:

$2x > 30+\frac{5}{4x} \\2x-\frac{5}{4x} > 30\\\frac{8x^2-5}{4x} > 30\\case~1\\if~x > 0\\8x^2-5 > 120x\\8x^2-120x > 5\\x^2-15x > \frac{5}{8} \\adding~(-\frac{15}{2} )^2~to~both~sides\\(x-\frac{15}{2} )^2 > \frac{5}{8}+\frac{225}{4} \\(x-\frac{15}{2} )^2 > \frac{455}{8} \\x-\frac{15}{2} < -\sqrt{\frac{455}{8} } \\x < \frac{15}{2}-\sqrt{\frac{455}{8} } \\or~x < 0\\rejected~as~x > 0$

$x-\frac{15}{2} > \sqrt{\frac{455}{8} } \\x > \frac{15}{2} +\sqrt{\frac{455}{8} }$

case~2

$if~x < 0\\8x^2-5 < 120x\\8x^2-120x < 5\\x^2-15x < \frac{5}{8} \\adding~(-\frac{15}{2} )^2\\(x-\frac{15}{2} )^2 < \frac{5}{8} +(-\frac{15}{2} )^2\\|x-\frac{15}{2} | < \frac{5+450}{8} \\-\sqrt{\frac{455}{8} } < x-\frac{15}{2} < \sqrt{\frac{455}{8} } \\\frac{15}{2} -\sqrt{\frac{455}{8} } < x < \frac{15}{2} +\sqrt{\frac{455}{8} } \\but~x < 0\\7.5-\sqrt{\frac{455}{8} } < x < 0$

8 0

1 year ago

PLZ HELP!! I NEED QUICKLY!!

djverab [1.8K]

Answer:

no worries about the other day and I had literally forgotten about the other night and was just so I could tell me how I felt and I had a flat rate that you and I had a

5 0

3 years ago

Read 2 more answers

A ball is thrown into the air with an upward velocity of 36 ft/s. Its height h in feet after t seconds is given by the function

FinnZ [79.3K]

Answer:

The ball reaches a height of 29.25 ft after 1.125 seconds

Step-by-step explanation:

The maximum height of a parabola can always be found by looking for the vertex. You can find the x value (or in this case the t value) of a vertex by using -b/2a in which a is the coefficient of x^2 and b is the coefficient of x.

-b/2a

-(36)/2(-16)

-36/-32

1.125 seconds

Now to find the height, we input that value in for t

h = -16t^2 + 36t + 9

h = -16(1.125)^2 + 26(1.125) + 9

29.25 feet

6 0

3 years ago

Read 2 more answers