II. f(x) doubles for each increase of 1 in the x values. Thus, r must be 2, and so we our ar^1 = 6 from ( I ) above becomes f(x) = a*2^x. Applying the restriction ar^1 = 6 results in f(1) = a*2^1 = 6, or a = 3.
Then f(x) = ar^x becomes f(x) = 3*2^2 (Answer A)
Based on the information given, the computation shows that the distance between them is 2.47 miles.
<h3>
Solving the distance.</h3>
Since one has bearing 41°45', this will be: = 41° + (45/60) = 41° + 0.75 = 41.75°.
The other has bearing 59°13'. This will be:
= 59° + (13/60) = 59° + 0.22 = 59.22°.
The difference of the angles will be:
= 59.22° - 41.75°
= 17.47°
Let the distance between them be represented by c. Therefore, we'll use cosine law to solve the question. This will be:
c² = a² + b² - 2ab cos 17.47°
c² = 20² + 20² - (2 × 20 × 20 × 0.19)
c² = 6.07459
c = 2.47
Learn more about distance on:
brainly.com/question/2854969
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Step-by-step explanation:
That should help
Answer:
The direction that the paraboa y=-4x^2-8x-13 open is
Down
(0,5.25)(10,13.75)
slope(m) = (y2 - y1) / (x2 - x1)
slope(m) = (13.75 - 5.25) / (10 - 0) = 8.5/10 = 0.85
y = mx + b
(0,5.25)...x = 0 and y = 5.25
slope(m) = 0.85
now we sub, we r looking for b, the y int
5.25 = 0.85(0) + b
5.25 = b
so ur equation is : y = 0.85x + 5.25 or C(t) = 0.85t + 5.25 <==
cost of a 12 min taxi ride.....sub in 12 for t
C(t) = 0.85t + 5.25
C(12) = 0.85(12) +5.25
C(12) = 10.20 + 5.25 = 15.45
so a 12 min ride would cost u : $ 15.45 <==
