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vlada-n [284]
4 years ago
6

The difference between two numbers is 2 and their product is 224. What are the numbers?

Mathematics
1 answer:
Sati [7]4 years ago
4 0

Let x,y be the two numbers. We have two pieces of information:

x-y=2 (the difference between the two numbers is 2)

xy=224 (their product is 224)

From the first equation, we can deduce x=y+2

If we plug this expression in the second equation, we have

xy = (y+2)y = 224 \iff y^2+2y-224 =0

If you solve this equation with the usual quadratic formula you get the solutions

y=-16,\quad y=14

So, you have the following couple of solutions, recalling that x is 2 more than y:

\begin{cases} x = -14\\y=-16\end{cases},\quad\begin{cases} x = 16\\y=14\end{cases}

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AnnyKZ [126]

Answer:

1) e = 6

2) w = 10

3) s = 27

4) t = 4

Step-by-step explanation:

Cross multiplication

3 0
3 years ago
For the funtion f(x)= (x+7)^5, Find f^-1 (x)
quester [9]

Answer:

The inverse of function f(x)= (x+7)^5 is \mathbf{f^{-1} (x)=\sqrt[5]{x}+7}

Option A is correct option.

Step-by-step explanation:

For the function f(x)= (x+7)^5, Find f^{-1} (x)

For finding inverse of x,

First let:

y=(x+7)^5

Now replace x with y and y with x

x=(y+7)^5

Now, solve for y

Taking 5th square root on both sides

\sqrt[5]{x}=\sqrt[5]{(y+7)^5}\\\sqrt[5]{x}=y+7\\=> y+7=\sqrt[5]{x}\\y=\sqrt[5]{x}-7

Now, replace y with f^{-1} (x)

f^{-1} (x)=\sqrt[5]{x}+7

So, the inverse of function f(x)= (x+7)^5 is \mathbf{f^{-1} (x)=\sqrt[5]{x}+7}

Option A is correct option.

6 0
3 years ago
Help i'll give 20points​
saul85 [17]

Step-by-step explanation:

512+18=530

423+12=435

5421+14=5435

6324+32=6356

7985+23=8008

5 0
3 years ago
Find m angle QSRIf m angle TSQ=15x , m angle TSR=173^ , and m angle QSR=10x-2
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{\color{red}{\huge{\underbrace{\overbrace{\mathfrak{\:\:\:\:\:\:\:꧁"Answer"꧂\:\:\: }}}}}}

\small\color{blak}{{\underline{\bold{ Find \:a X } } }  }

\small\color{black}{{\underline{\bold{173°=15z+10x-2 } } }  } \\  = 173 = 25x - 2 \\  =  - 25x =  - 2 - 173 \\  =  - 25x - 175 \\  = \small\color{blue}{{{\boxed{\tt\red{} \:\:\:\:\:\:\:\:\:\: x=7\:\:\:\: }}}}

\small\color{blak}{{\underline{\bold{ Find\:a\:m

\small\color{blak}{{\underline{\bold{ 10(7)-2 } } }  }\\=70-2\\=\small\color{red}{{{\boxed{\tt\red{} \:\:\:\:\:\:\:\:\:\: m

\Large\color{red}{{\underline{\mathfrak {{꧁"Carry\:on\: learning"꧂ }}}}}

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3 years ago
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