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11Alexandr11 [23.1K]
3 years ago
13

1 n +5 - 1 n2 + n n2 +n n-6 n +1

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
6 0
1). 1n+5-1
N=26
2). n2+n n2+n
n3+n2+n
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A1,a2,a3....a30-each of these 30 sets has 5 elements.b1,b2,....bn-each of these n sets has 3 elements.union of a1,a2...a30=union
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 the number of elements in the union of the A sets is:5(30)−rAwhere r is the number of repeats.Likewise the number of elements in the B sets is:3n−rB
Each element in the union (in S) is repeated 10 times in A, which means if x was the real number of elements in A (not counting repeats) then 9 out of those 10 should be thrown away, or 9x.  Likewise on the B side, 8x of those elements should be thrown away. so now we have:150−9x=3n−8x⟺150−x=3n⟺50−x3=n
Now, to figure out what x is, we need to use the fact that the union of a group of sets contains every member of each set.  if every element in S is repeated 10 times, that means every element in the union of the A's is repeated 10 times.  This means that:150 /10=15is the number of elements in the the A's without repeats counted (same for the Bs as well).So now we have:50−15 /3=n⟺n=45
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The standard form of a linear equation is ax+by=c, where a , b, and c are constants in the equation.

Based on the equation you have provided, the standard form would be -3x+4y=12, where a=-3, b=4, c=12.

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