Answer:
The y-intercept of the equation is 100 and represents the initial studio-use fee.
Step-by-step explanation:
In this equation, our t variable (time) is the equivalent of the x-variable on a graph. This is because it is the variable that we 'change' to see its impact on y. We see how the amount of hours affects the price. So our P variable (price) is the equivalent of y on a graph. The y-intercept is where the line crosses the y-axis on a graph. At this point, x=0.
Since P is our y, and t is our x, to find the y-intercept, we simply need to make t = 0.
P = 50(0) + 100
P = 100
Therefore the y-intercept is 100.
In this context, t represents time, so even though the studio has been used for 0 hours, the price is still 100. This is because the 100 represents the initial studio-use fee, and using it for certain amounts of time adds onto the initial fee of $100. The hourly fee is represented by 50t so it costs $50 more for each hour of use.
Hope this helped!
1. Divide 135 by 8 which is equal to 16
2. Multiply 16 ×8 = 128
3. Subtract 135 - 128 =7
The seven represent the numerator so it would be 7/8.
The finally answer would be
I need to know how many miles the race is
Answer is below.
<em>(Note to asker: Lack of explanations can get my answer deleted)</em>
<em />
<u><em>Step 1</em></u>
We'll to isolate the variable, but to do that, get rid of the coefficient that multiplies it.
To do that, divide both sides by 22.
<em><u>Step 2.</u></em>
Now we have divided both sides by 22, but we'll need to reduce the fraction 
.
We can reduce the fraction by dividing the factors that are in the numerator and denominator.
That being said, 22 appears both in the numerator and denominator.
<u><em>Step 3</em></u>
Now, for 
, we'll need to reduce it to the lowest terms. Like in the 2nd step, we'll divide factors that are in the numerator and denominator.
That being said, 2 appears both in the numerator and denominator.
Hence, M = 5/11
9514 1404 393
Answer:
a[n] = n^2 -3n -6
Step-by-step explanation:
First differences are ...
-8 -(-8) = 0
-6 -(-8) = 2
-2 -(-6) = 4
Second differences are ...
2 -0 = 2
4 -2 = 2
Constant second differences indicate a degree 2 (quadratic) sequence.
The general formulation can be written as ...
an = a1 +(n -1)(d1 +(n -2)/2(d2)) . . . . where a1 is the first term; d1 is the first first difference; d2 is the second difference
= -8 +(n -1)(0 +(n -2)/2(2)) = -8 +(n -1)(n -2)
an = n^2 -3n -6 . . . . . formula for the n-th term
