The length of a rectangle is 4 meters longer than the width. if the area is 21 square meters, find the rectangle's dimensions. round to the nearest tenth of a meter.
Answer:
11x + 8y
Step-by-step explanation:
(5x + 5y) + 3 ( 3 · 2x + 3y)
(5x + 5y) + (6x + 3y)
5x + 5y + 6x + 3y
5x + 6x + 5y + 3y
11x + 8y
Answer:
.4!
Step-by-step explanation:
first you divide 20 by 125 and get .16
then you take the square root of .16 and get .4
Okay so you would use PEMDAS (parentheses, exponents, multiply, divide, add, and subtract) so there are no parentheses so you do the exponents

then you do the rest so 100+36=136 and then 136-9=127 so the answer is 127
Answer:
sorry man I really don't know hopefully you can find an answer